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How many formula units does 200 grams of Calcium Carbonate represent?
Well, darling, to find the number of formula units in 200 grams of Calcium Carbonate, you first need to calculate the molar mass of CaCO3. Once you do the math, you'll find that one mole of CaCO3 weighs 100.09 grams. So, 200 grams of CaCO3 represents 2 moles of the compound, which is equivalent to 2 times Avogadro's number (6.022 x 10^23) formula units. Voilà!
What is the concentration of a 450ml solution that contains 200 grams of iron chloride?
To calculate the concentration of the iron chloride solution, we need to convert the mass of iron chloride (200 grams) to moles using the molar mass of iron chloride (FeCl3). Then, divide the number of moles by the volume of the solution (450 ml converted to liters) to get the concentration in moles per liter (M).
How many milligrams of calcium are present in 500 mg tablet of calcium carbonate?
The formula for calcium carbonate is CaCO3, and it has a gram formula mass of 100.09. The formula shows that each formula mass contains one calcium atom, which has a gram atomic mass of 40.08. Therefore, the mass fraction of calcium in calcium carbonate is 40.08/100.09, so that a 500 mg tablet of calcium carbonate contains 200 mg of calcium, to the justified number of significant digits.
What mass of ammonium chlorate is needed to decompose to give off 200 liters of oxygen?
The molar volume of gas at STP is 22.4 L/mol. So, 200 L of oxygen is equivalent to 200/22.4 = 8.93 moles. The balanced chemical equation for the decomposition of ammonium chlorate is 2NH4ClO3 -> 2N2 + Cl2 + 3O2. Therefore, to produce 3 moles of oxygen, we need 2 moles of ammonium chlorate. 8.93 moles of oxygen would require 2/3 * 8.93 = 5.95 moles of ammonium chlorate. The molar mass of NH4ClO3 is 101.5 g/mol, so the mass of ammonium chlorate needed would be 5.95 * 101.5 = 604.5 grams.
How many grams of NaCl are required to prepare 4000 mL of 5 percent solution?
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
How many moles are in 1200 grams of calcium bromide?
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
How many moles are there in 200 grams of Calcium Carbonate?
For a partly ionically bonded compound such as calcium carbonate, the gram formula mass is substituted for a mole, which technically exists only for purely covalently bonded compounds. The gram formula mass for calcium carbonate is 100.09. Therefore, 200 grams constitutes 200/100.09 or 2.00 gram formula masses of calcium carbonate, to the justified number of significant digits.
How many moles of sucrose are in 200 grams?
To calculate the number of moles of sucrose in 200 grams, you need to divide the given mass by the molar mass of sucrose. The molar mass of sucrose is approximately 342 grams/mol. Therefore, 200 grams of sucrose is equal to 0.585 moles.
How many formula units does 200 grams of Calcium Carbonate represent?
Well, darling, to find the number of formula units in 200 grams of Calcium Carbonate, you first need to calculate the molar mass of CaCO3. Once you do the math, you'll find that one mole of CaCO3 weighs 100.09 grams. So, 200 grams of CaCO3 represents 2 moles of the compound, which is equivalent to 2 times Avogadro's number (6.022 x 10^23) formula units. Voilà!
How many moles of CH4 are in 200 grams of CH4?
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The mass in grams of 2.8 moles aluminum?
200
Which value most closely represents the number of grams in 9.0 moles of calcium metal 200 g Ca 6.02 x 1023 g Ca 400 g Ca 360 g Ca?
9,0 moles of calcium is equal to 360,702 g.
How many grams are in 200 grams?
There are 200 grams in 200 grams.
How many grams of calcium chloride would you dissolve in water to make a 0.2 M CaCl2 solution with 200 ml final volume?
To make a 0.2 M CaCl2 solution with a final volume of 200 ml, you would need to dissolve 8.8 grams of calcium chloride (CaCl2) in water. This calculation is based on the molar mass of CaCl2 (110.98 g/mol) and the formula for calculating molarity (moles = molarity x volume in liters).
How many grams are there in 200 g of ammonia?
There are 200 grams of ammonia in 200 grams of ammonia.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
What is the mass of 200 moles of Fe?
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
