200g times 342.2965 g/mol = 68459.3 moles
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
There are 200 grams of ammonia in 200 grams of ammonia.
200 grams = 200,000 milligrams
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
200 g CH4 x 1 mole CH4/16 g = 12.5 moles CH4
The molecular weight of Calcium Bromide is extremely close to 200. So 1200/200 = 6 moles present.
200
There are 200 grams in 200 grams.
To make 400 ml of a 50% sucrose solution, you would mix 200 ml of sucrose with 200 ml of water. Measure out 200 ml of sucrose and dissolve it in 200 ml of water, ensuring the sucrose is completely dissolved to create the 50% solution.
There are 200 grams of ammonia in 200 grams of ammonia.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
To calculate the molarity, you first need to convert the grams of sugar to moles. The molar mass of sugar (sucrose) is about 342 g/mol. So, 15 g / 342 g/mol = 0.044 moles of sugar. Next, convert the volume of the solution to liters by dividing 200 ml by 1000 to get 0.2 L. Finally, divide the moles of sugar by the liters of solution: 0.044 moles / 0.2 L = 0.22 M. So, the molarity of the solution is 0.22 M.
200 grams = 200,000 milligrams
There is 0.440925 Pounds in 200 Grams.