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How many moles grams are in 24.6 moles of Fe?
To convert moles to grams, you need to multiply by the molar mass of the element. The molar mass of Fe (iron) is approximately 55.85 g/mol. For 24.6 moles of Fe, the mass in grams would be 24.6 moles x 55.85 g/mol = 1373.31 grams (approximately).
What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
How many moles are present in 1.68g of iron?
To calculate the number of moles in 1.68g of iron, we need to use the molar mass of iron, which is approximately 55.85 g/mol. Divide the mass of iron (1.68g) by its molar mass to find the number of moles present. Therefore, there are approximately 0.03 moles of iron in 1.68g.
How many moles in 8200G of Fe?
To determine the number of moles in 8200 g of Fe, you first need to calculate the molar mass of Fe, which is approximately 55.845 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 8200 g ÷ 55.845 g/mol ≈ 146.7 moles of Fe.
What is the number of moles of 200g of Fe?
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
How many moles are in 23 g of Fe?
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
How many moles Fe are in a sample of Fe2O3 that contains 100g O?
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
.41 grams FE is how many moles Fe?
For this you need the atomic mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel..410 grams Fe / (55.9 grams) = .00733 moles Fe
What is the mass of 2.25 moles of iron?
The answer is 125,65 g.
How many moles grams are in 24.6 moles of Fe?
To convert moles to grams, you need to multiply by the molar mass of the element. The molar mass of Fe (iron) is approximately 55.85 g/mol. For 24.6 moles of Fe, the mass in grams would be 24.6 moles x 55.85 g/mol = 1373.31 grams (approximately).
What is the mass of 200 moles of NH3?
To find the mass of 200 moles of NH3 (ammonia), you'll need to know the molar mass of NH3, which is approximately 17.03 g/mol. Multiply the molar mass by the number of moles to get the mass: 17.03 g/mol x 200 mol = 3406 g. Therefore, the mass of 200 moles of NH3 is 3406 grams.
How many moles are in 103.56 g of Fe3(PO4)2?
To find the number of moles in 103.56 g of Fe₃(PO₄)₂, first calculate its molar mass. The molar mass of Fe₃(PO₄)₂ is approximately 357.43 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 103.56 g / 357.43 g/mol ≈ 0.29 moles.
How many moles are I am 223.2 g iron (Fe)?
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
What mass of ironIIInitrate is needed for a chemical reaction that requires 6.00 moles of FeNO33?
To determine the mass of iron(II) nitrate needed for 6.00 moles of Fe(NO3)2, you first need to calculate the molar mass of Fe(NO3)2. Fe(NO3)2 has a molar mass of approximately 179.86 g/mol. Therefore, the mass needed would be 6.00 moles * 179.86 g/mol ≈ 1079.16 grams of Fe(NO3)2.
The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
How many moles are present in 1.68g of iron?
To calculate the number of moles in 1.68g of iron, we need to use the molar mass of iron, which is approximately 55.85 g/mol. Divide the mass of iron (1.68g) by its molar mass to find the number of moles present. Therefore, there are approximately 0.03 moles of iron in 1.68g.
