The molecular mass of iron(III) chloride is 55.8 + 3(35.5) = 162.3
Amount of iron (III) chloride in a 80.5g pure sample = 80.5/162.3 = 0.496mol
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
1 mole Fe = 6.022 x 1023 atoms Fe1 mole Fe = 55.845g Fe (atomic weight in grams)Convert grams Fe to moles Fe.400g Fe x (1mol Fe/55.845g Fe) = 7.16mol FeConvert moles Fe to atoms Fe.7.16mol Fe x (6.022 x 1023atoms Fe/1mol Fe) = 4.31 x 1024 atoms Fe
To convert moles to grams, you need to multiply by the molar mass of the element. The molar mass of Fe (iron) is approximately 55.85 g/mol. For 24.6 moles of Fe, the mass in grams would be 24.6 moles x 55.85 g/mol = 1373.31 grams (approximately).
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
55.8 moles
Approx 3.997 moles.
6 moles
55.8 moles
To determine the number of moles of Fe that can be made from 25 moles of Fe2O3, you need to write the balanced chemical equation for producing O2 from Fe2O3. 2Fe2O3 = 4Fe + 3O2, which means that 2 moles of Fe2O3 will produce 4 moles of Fe and 3 moles of O2 . Set up a proportion. 3 moles of O2 ÷ 2 moles of Fe2O3 = x moles of O2 ÷ 25 moles of Fe2O3 Cross multiply and divide. 3 moles of O2 * 25 moles of Fe2O3 ÷ 2 moles of Fe2O3 = 37.5 moles of O2 produced.
For this you need the atomic mass of Fe. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel..410 grams Fe / (55.9 grams) = .00733 moles Fe
To find the number of moles in 23 g of Fe, first find the molar mass of Fe by looking up the atomic weight on the periodic table. Fe has a molar mass of approximately 55.85 g/mol. Divide the given mass by the molar mass to find the number of moles: 23 g Fe / 55.85 g/mol = approximately 0.41 moles of Fe.
To find the number of atoms in 4.80 moles of Fe, you need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol. So, 4.80 moles of Fe would contain: 4.80 moles x 6.022 x 10^23 atoms/mol = 2.89 x 10^24 atoms of Fe.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
To find the number of moles of Fe in Fe2O3, first calculate the molar mass of Fe2O3 and O. Then, determine the number of moles of O in the sample. Finally, you can use the stoichiometry of Fe2O3 to find the moles of Fe present. Alternatively, if you know the molar mass of just Fe, you can calculate the moles of Fe by dividing the mass of Fe in the sample by its molar mass.
233,2 g iron Feis equivalent to 4,176 moles.
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.