23 grams iron ( 1mole Fe/55.85 grams)
= 0.41 moles of iron
233,2 g iron Feis equivalent to 4,176 moles.
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
To determine how many grams of Fe can be produced from 10.0 g of Al reacting with Fe2O3, we first need the balanced chemical equation for the reaction: [ 4Al + 3Fe2O3 \rightarrow 4Fe + 6Al2O3 ] From the equation, 4 moles of Al produce 4 moles of Fe. The molar mass of Al is approximately 27 g/mol, so 10.0 g of Al corresponds to about 0.37 moles of Al. This produces an equivalent of 0.37 moles of Fe. Given that the molar mass of Fe is about 56 g/mol, the mass of Fe produced is approximately (0.37 , \text{moles} \times 56 , \text{g/mol} \approx 20.72 , \text{g}).
This amount may be different because rust is not a clearly definite compound.
For this you need the atomic (molecular) mass of FeCl3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. FeCl3=162.4 grams .200 moles FeCl3
To determine the number of atoms in 12.5 g of Fe, you need to first calculate the number of moles of Fe using its molar mass (55.84 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
233,2 g iron Feis equivalent to 4,176 moles.
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
There are approximately 3.25 x 10^24 iron atoms in 354 g of iron. This calculation is done by converting the mass of iron to moles using the molar mass of iron, and then using Avogadro's number to convert moles to atoms.
The answer is 125,65 g.
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.
To find the number of atoms we need to find number of moles of Fe in 312.0 grams. Molar weight of Fe = 56 Number of moles of Fe in 312 grams = 312/56 =5.571 moles. 1 mole of Fe has Avogadro number of atoms. So 5.571 moles of Fe has atoms = 5.571 * Avogadro number. Avogadro number = 6.022 * 10^23 So total atoms = 5.571 * 6.022 * 10^23 = 33.548 * 10^23 * means multiply, ^ means raised to power.
This amount may be different because rust is not a clearly definite compound.
To determine the number of moles in 223.2 grams of iron (Fe), you will first need to divide the given mass (223.2 g) by the molar mass of iron, which is approximately 55.85 g/mol. This calculation will give you the number of moles of iron in 223.2 grams.