23 grams iron ( 1mole Fe/55.85 grams)
= 0.41 moles of iron
233,2 g iron Feis equivalent to 4,176 moles.
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
To find the number of moles in 103.56 g of Fe₃(PO₄)₂, first calculate its molar mass. The molar mass of Fe₃(PO₄)₂ is approximately 357.43 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 103.56 g / 357.43 g/mol ≈ 0.29 moles.
To determine how many grams of iron can be produced from 250.0 g of Fe₂O₃, we first need to use the molar mass of Fe₂O₃, which is approximately 159.69 g/mol. The balanced chemical reaction for the reduction of Fe₂O₃ to iron is: Fe₂O₃ → 2 Fe + 1.5 O₂. From the stoichiometry of the reaction, 1 mole of Fe₂O₃ produces 2 moles of Fe. Thus, 250.0 g of Fe₂O₃ corresponds to about 1.56 moles, yielding approximately 3.12 moles of Fe, which is about 174.0 g of iron.
To determine how many grams of Fe can be produced from 10.0 g of Al reacting with Fe2O3, we first need the balanced chemical equation for the reaction: [ 4Al + 3Fe2O3 \rightarrow 4Fe + 6Al2O3 ] From the equation, 4 moles of Al produce 4 moles of Fe. The molar mass of Al is approximately 27 g/mol, so 10.0 g of Al corresponds to about 0.37 moles of Al. This produces an equivalent of 0.37 moles of Fe. Given that the molar mass of Fe is about 56 g/mol, the mass of Fe produced is approximately (0.37 , \text{moles} \times 56 , \text{g/mol} \approx 20.72 , \text{g}).
To determine the number of atoms in 12.5 g of Fe, you need to first calculate the number of moles of Fe using its molar mass (55.84 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
To find the number of moles of Fe in 14.2 g of Fe2O3, we need to use the molar mass of Fe2O3 (molecular weight = 159.69 g/mol) and the ratio of Fe to Fe2O3. There are 2 moles of Fe in 1 mole of Fe2O3, so we find the moles of Fe in 14.2 g of Fe2O3 by: (14.2 g / 159.69 g/mol) * 2 = 0.249 moles of Fe.
233,2 g iron Feis equivalent to 4,176 moles.
To find the number of moles of iron (Fe) in 223.2 g, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of iron is approximately 55.85 g/mol. Thus, moles of iron = 223.2 g / 55.85 g/mol ≈ 3.99 moles.
To find the number of moles in 103.56 g of Fe₃(PO₄)₂, first calculate its molar mass. The molar mass of Fe₃(PO₄)₂ is approximately 357.43 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 103.56 g / 357.43 g/mol ≈ 0.29 moles.
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
To determine how many grams of iron can be produced from 250.0 g of Fe₂O₃, we first need to use the molar mass of Fe₂O₃, which is approximately 159.69 g/mol. The balanced chemical reaction for the reduction of Fe₂O₃ to iron is: Fe₂O₃ → 2 Fe + 1.5 O₂. From the stoichiometry of the reaction, 1 mole of Fe₂O₃ produces 2 moles of Fe. Thus, 250.0 g of Fe₂O₃ corresponds to about 1.56 moles, yielding approximately 3.12 moles of Fe, which is about 174.0 g of iron.
There are approximately 3.25 x 10^24 iron atoms in 354 g of iron. This calculation is done by converting the mass of iron to moles using the molar mass of iron, and then using Avogadro's number to convert moles to atoms.
The answer is 125,65 g.
To determine how many grams of Fe can be produced from 10.0 g of Al reacting with Fe2O3, we first need the balanced chemical equation for the reaction: [ 4Al + 3Fe2O3 \rightarrow 4Fe + 6Al2O3 ] From the equation, 4 moles of Al produce 4 moles of Fe. The molar mass of Al is approximately 27 g/mol, so 10.0 g of Al corresponds to about 0.37 moles of Al. This produces an equivalent of 0.37 moles of Fe. Given that the molar mass of Fe is about 56 g/mol, the mass of Fe produced is approximately (0.37 , \text{moles} \times 56 , \text{g/mol} \approx 20.72 , \text{g}).
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
The molar mass of Fe (iron) is 55.85 g/mol. Therefore, the mass of 200 moles of Fe would be 200 moles × 55.85 g/mol = 11,170 g or 11.17 kg.