0
1.35 x 10^23 molecules
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How many iron atoms are contained in 354 g of iron?
354 g Fe x 1 mole Fe/55.85 g Fe x 6.02x10^23 atoms Fe/mole Fe = 3.82x10^24 atoms of iron
How many iron atoms are present in a 23.0 g iron block?
1 mole Fe = 55.845g Fe 1 mole Fe = 6.022 x 1023 atoms Fe 23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe) = 2.40 x 1023 atoms Fe
What number of Fe atoms and what amount of Fe atoms are in 500 g of Fe?
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
How many atoms are there in 1 cm3 of iron?
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
How many moles of nickel (Ni) atoms are in 125 g Ni?
There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
How many iron atoms are contained in 354 g of iron?
354 g Fe x 1 mole Fe/55.85 g Fe x 6.02x10^23 atoms Fe/mole Fe = 3.82x10^24 atoms of iron
How many iron atoms re contained in 354 g of iron?
3.82 × 1024 Fe atoms
How many iron atoms are present in a 23.0 g iron block?
1 mole Fe = 55.845g Fe 1 mole Fe = 6.022 x 1023 atoms Fe 23.0g Fe x (1 mole Fe/55.845g Fe) x (6.022 x 1023 atoms Fe/1 mole Fe) = 2.40 x 1023 atoms Fe
What number of Fe atoms and what amount of Fe atoms are in 500 g of Fe?
Known/Given:1 mole of Fe = 55.845g Fe (its atomic weight in grams)1 mole of Fe = 6.022 x 1023 atoms Fe (from Avogadro's number)Convert grams Fe to moles Fe.600.0g Fe x 1mol Fe/55.845g Fe = 10.74mol FeConvert moles Fe to atoms Fe.10.74mol Fe x 6.022 x 1023atoms Fe/1mol Fe = 6.468 x 1024atoms Fe
How many atoms are there in 1 cm3 of iron?
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
How many moles of nickel (Ni) atoms are in 125 g Ni?
There are 58.6934 gram in one mole of Ni atoms, so there are125(g Ni) / 58.6934 (g.mol-1 Ni) = 2.13 moles in 125 gram Ni
Which one has more no of atoms 10 g of Al or 10 g of Fe?
10 g of Al
How many atoms are in 26.1 g of Fe?
An atom's atomic number gives its number of protons. Checking the periodic table for atomic number 26, we see that its represented by the element iron. Thus, iron does have 26 protons.
Which has more atoms 3.0 grams of iron Fe or 2.0 grams of sulfur?
3.0 g Fe x 1 mole Fe/55.8 g = 0.054 moles Fe2.0 g S x 1 mole S/32 g = 0.063 moles STherefore there are more molecules of S than of Fe since one mole of either = 6.02x10^23 atoms.
How many moles of nitrogen atoms are present in 53.55 g of FeNO32?
Molar mass of Fe(NO3)2 is 55.85 + 2(14.00 + 3(16.00)) = 179.85 g/mol Therefore, number of moles of Fe(NO3)2 present is 53.55/179.85 = 0.2977 mol For each molecule of Fe(NO3)2, there are two atoms of nitrogen associated with it. Therefore, there are 0.2977*2 = 0.5954 mol of nitrogen atoms
How many atoms are found in 600 grams of iron?
To find the number of atoms we need to find number of moles of Fe in 312.0 grams. Molar weight of Fe = 56 Number of moles of Fe in 312 grams = 312/56 =5.571 moles. 1 mole of Fe has Avogadro number of atoms. So 5.571 moles of Fe has atoms = 5.571 * Avogadro number. Avogadro number = 6.022 * 10^23 So total atoms = 5.571 * 6.022 * 10^23 = 33.548 * 10^23 * means multiply, ^ means raised to power.
How many atoms are in 5.0 mole of Fe?
Fe, or iron, has a molar mass of 55.845 grams per mole. This means that 0.2 moles is equal to 11.2 grams of iron.
