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How many moles are in 125g of Zn?
The equivalent of 125 g zinc is 1, 91 moles.
How many moles of air are there in a 125 mL flask if the pressure is 739 torr and the temperature is 18C?
To find the number of moles of air in the flask, we need to use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. First, convert the volume to liters (125 mL = 0.125 L) and the temperature to Kelvin (18°C + 273 = 291 K). Then, calculate the number of moles: n = (PV) / (RT). Substituting the values, we get n = (739 torr * 0.125 L) / (0.0821 L atm/mol K * 291 K). Calculate to find the number of moles.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many half-lives have elapsed to yield a sample with 125 atoms of C-14 and 375 atoms of N-14?
To determine the number of half-lives that have elapsed, we first find the total number of atoms in the sample, which is 500 (125 + 375). The starting atom would have been from 250 atoms of C-14. To find the number of half-lives elapsed, we divide the total number of atoms by the starting amount (500/250). This gives us 2 half-lives that have elapsed.
How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution?
To calculate the amount of KCl needed, we first need to find the number of moles of KCl required using the formula: moles = Molarity x Volume (in L). Then, we convert moles to grams using the molar mass of KCl, which is 74.55 g/mol. Finally, we use the formula: grams = moles x molar mass to find that approximately 6.33 grams of KCl are needed to prepare 125 mL of a 0.720 M solution.
How many moles of nickel (Ni) are there in 125 g of Ni?
125 g nickel is equivalent to 2,13 moles.
How many atoms are in 125 grams of Calcium?
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
If you have 125 grams of zinc how many moles of zinc do you have?
To calculate the number of moles of zinc, use the formula: moles = mass (grams) / molar mass (grams/mol). The molar mass of zinc (Zn) is approximately 65.38 g/mol. Therefore, 125 grams of zinc is equal to 125 g / 65.38 g/mol, which is about 1.91 moles of zinc.
How many nickels are in 125 dollars?
A nickel is 5 cents so there are 20 nickels in one dollar. 125 dollars would then be 20 * 125 = 2500 nickels.
How many moles of mercury (II) oxide are needed to produce 125 g of oxygen?
To determine how many moles of mercury (II) oxide (HgO) are needed to produce 125 g of oxygen (O₂), we first need to consider the decomposition reaction: 2 HgO(s) → 2 Hg(l) + O₂(g). From this equation, we see that 2 moles of HgO produce 1 mole of O₂. The molar mass of O₂ is approximately 32 g/mol, so 125 g of O₂ corresponds to about 3.91 moles (125 g ÷ 32 g/mol). Therefore, since 2 moles of HgO produce 1 mole of O₂, we need 7.82 moles of HgO (3.91 moles O₂ × 2 moles HgO/mole O₂).
What is 125 gof HSO in moles form?
No such thing as HSO in chemistry. If you're referring to H2SO4, which is sulfuric acid, then 125 grams of it would be: H2SO4 = 98g/mol; 98/1=125/x; solve for x to get about 1.28 moles.
How many quarters makes 25 nickels?
A nickel is 5 cents so 25 nickels is 25*5 = 125 cents. A quarter is 25 cents so 125 cents = 125/25 = 5 coins.
How many moles are in 125g of Zn?
The equivalent of 125 g zinc is 1, 91 moles.
How many grams of P2O5 will be produced from 125 g of P?
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
How many moles of mercury are produced if 125 g of oxygen is also produced?
To determine how many moles of mercury are produced when 125 g of oxygen is generated, we first need to know the balanced chemical equation for the reaction involving mercury and oxygen. Assuming the reaction is the formation of mercury(II) oxide (HgO) from mercury (Hg) and oxygen (O₂), the equation is: 2 Hg + O₂ → 2 HgO. Given that the molar mass of oxygen (O₂) is approximately 32 g/mol, 125 g of oxygen corresponds to about 3.91 moles of O₂. According to the stoichiometry of the balanced equation, 2 moles of Hg are produced for every 1 mole of O₂. Therefore, 3.91 moles of O₂ would produce approximately 7.82 moles of Hg.
How many moles of air are there in a 125 mL flask if the pressure is 739 torr and the temperature is 18C?
To find the number of moles of air in the flask, we need to use the ideal gas law equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin. First, convert the volume to liters (125 mL = 0.125 L) and the temperature to Kelvin (18°C + 273 = 291 K). Then, calculate the number of moles: n = (PV) / (RT). Substituting the values, we get n = (739 torr * 0.125 L) / (0.0821 L atm/mol K * 291 K). Calculate to find the number of moles.
Convert 125 grams of calcium to moles?
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.125 grams Ca / (40.1 grams) = 3.12 moles Ca
