How many moles are in 103.56 g of Fe3(PO4)2?

Answer 1

To find the number of moles in 103.56 g of Fe₃(PO₄)₂, first calculate its molar mass. The molar mass of Fe₃(PO₄)₂ is approximately 357.43 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we get: moles = 103.56 g / 357.43 g/mol ≈ 0.29 moles.