978 g calcium contain 24,4 moles.
425 g calcium (Ca) is equal to 10,604 moles.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
To find the number of moles in 16.4 g of calcium nitrate, Ca(NO3)2, you first need to calculate its molar mass. The molar mass of Ca(NO3)2 is approximately 164.1 g/mol. Using the formula for moles (moles = mass / molar mass), you can calculate the moles: ( \text{moles} = \frac{16.4 , \text{g}}{164.1 , \text{g/mol}} \approx 0.100 , \text{moles} ). Therefore, there are about 0.100 moles of Ca(NO3)2 in 16.4 g.
To find the number of moles of calcium (Ca) in 40.1 grams, you can use the formula: moles = mass (g) / molar mass (g/mol). The molar mass of calcium is approximately 40.08 g/mol. Therefore, the calculation is 40.1 g / 40.08 g/mol, which is about 1.0005 moles of calcium.
To find the number of moles in 12.0 g of calcium hydroxide, Ca(OH)₂, you first need to calculate its molar mass. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol (calcium: 40.08 g/mol, oxygen: 16.00 g/mol, hydrogen: 1.01 g/mol). Using the formula ( \text{moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ), you can calculate the moles: ( \frac{12.0 , \text{g}}{74.09 , \text{g/mol}} \approx 0.162 , \text{moles} ). Thus, there are approximately 0.162 moles of Ca(OH)₂ in 12.0 g.
425 g calcium (Ca) is equal to 10,604 moles.
156 g calcium is equivalent to 3,89 moles.
0,688 g calcium is equivalent to 0,017 moles.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
40 g of Ca = 1 mole So 808 g of Ca = 20.2 mole
To find the number of moles, you need to divide the given mass of calcium by its molar mass. The molar mass of calcium (Ca) is approximately 40.08 g/mol. Number of moles = 77.4 g / 40.08 g/mol ≈ 1.93 moles.
9,0 moles of calcium is equal to 360,702 g.
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
First, determine the moles of each element: moles of Ca = 13.5 g / 40.08 g/mol = 0.336 moles moles of O = 10.8 g / 16.00 g/mol = 0.675 moles moles of H = 0.675 g / 1.01 g/mol = 0.668 moles Next, divide each mole value by the smallest mole value to get the ratio of atoms. The ratio is roughly 0.5 Ca to 1 O to 1 H. Therefore, the empirical formula of the compound is Ca(OH)2.
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.