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How many moles of ions are in 2 moles of CaOH2?
2 moles of Ca and 4 moles of OH
How many moles of calcium are in 425 g calcium (Ca)?
425 g calcium (Ca) is equal to 10,604 moles.
How many moles of ca would be in 3.8G?
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles of atoms are present in 4 moles of Ca(HCO3)2?
In Ca(HCO3)2, there are 2 moles of carbonate ions (CO3^2-), each containing 3 atoms. So there are 6 atoms in 1 molecule of Ca(HCO3)2. Therefore, in 4 moles of Ca(HCO3)2, there are 4 x 6 = 24 moles of atoms.
How many grams are there in .761 moles of Ca?
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
How many moles of Ca are there in 0.18moles of Ca F2?
There are 0.18 moles of Ca2+ ions in 0.18 moles of CaF2.
How many atoms would 3 moles of Ca have?
3 x 6.02E23 molecules.
How many moles of calcium is 126g of ca?
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
How many moles of calcium atoms are in 45.8 g of Ca?
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.
How many moles of water are needed to exactly react with 2.0 moles of Ca?
To determine how many moles of water are needed to react with 2.0 moles of calcium (Ca), we first need to consider the chemical reaction between calcium and water. The balanced equation is: [ \text{Ca} + 2 \text{H}_2\text{O} \rightarrow \text{Ca(OH)}_2 + \text{H}_2 ] From the equation, 1 mole of calcium reacts with 2 moles of water. Therefore, for 2.0 moles of calcium, you would need ( 2.0 , \text{moles Ca} \times 2 , \text{moles H}_2\text{O}/\text{mole Ca} = 4.0 , \text{moles H}_2\text{O} ). Thus, 4.0 moles of water are required.
How many moles of atom contained in 0.688 g Ca?
0,688 g calcium is equivalent to 0,017 moles.
