0
What else can I help you with?
How many moles of molecules are there in 38g of fluorine F2?
To calculate the number of moles of F2 molecules in 38g, we first need to determine the molar mass of F2, which is 38 grams/mol. Next, we can use the formula: moles = mass / molar mass. Therefore, the number of moles in 38g of F2 is 1 mole.
5f2 2nh3 yields n2f4 6hf if you have 69.3 g nh3 how many grams of f2 are required for complete reaction?
To find the grams of F2 required for the reaction, first calculate moles of NH3: 69.3 g NH3 / 17.03 g/mol = 4.07 moles NH3. From the balanced equation, 5 moles of NH3 react with 2 moles of F2, so you need 4.07 moles NH3 * (2 moles F2 / 5 moles NH3) * 38.0 g/mol = 30.6 g of F2 for complete reaction.
The partial pressure of F2 in a mixture of gases where the total pressure is 1atm is 300 torr what is the mole fraction of F2?
0.395 total moles moles F 760.torr 300.torr total moles moles F 2 2 = ×
How many liters of fluorine gas will it take to convert 100 grams of C2H4 to C2H4F2 using the following reaction?
The balanced reaction for converting 1 mol of C2H4 to C2H4F2 using F2 gas is: C2H4 + 2 F2 -> C2H4F2 First, calculate the moles of C2H4 in 100g. Then, using the mole ratio from the balanced equation, determine how many moles of F2 are needed. Finally, convert the moles of F2 to liters using the ideal gas law (PV = nRT) at the given conditions.
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
To determine the number of moles of fluorine present in 2.67 grams of nitrogen trifluoride (NF3), we first need to calculate the molar mass of NF3, which is 71.0 g/mol. Then we find the moles of NF3 in 2.67 g by dividing the mass by the molar mass: 2.67 g / 71.0 g/mol ≈ 0.038 moles. As there are three fluorine atoms in each molecule of NF3, there are 3 times more moles of fluorine: 0.038 moles NF3 x 3 = 0.114 moles of fluorine.
How many gram of f2 are required to react with 3.50 moles of nh3?
The balanced chemical equation for the reaction between F2 and NH3 is: 3 F2 + 4 NH3 -> 6 HF + N2 From the equation, we can see that 3 moles of F2 react with 4 moles of NH3. To find the moles of F2 required to react with 3.50 moles of NH3, we can set up a proportion: 3 moles F2 / 4 moles NH3 = x moles F2 / 3.50 moles NH3 Solving for x, we find that 2.625 moles of F2 are required. To convert this to grams, we use the molar mass of F2 which is approximately 38.00 g/mol. 2.625 moles F2 x 38.00 g/mol = 99.75 grams of F2 required to react with 3.50 moles of NH3.
How many moles F2 are required to produce 3.0 moles KrF6 in the equation Kr plus 3F2 producing KrF6?
Given the balanced equation Kr + 3F2 --> KrF6 In order to find how many moles of F2 are needed to produce 3.0 moles of KrF6, we must convert from moles to moles (mol --> mol conversion). 3.0 mol KrF6 * 3 molecules F2 = 9.0 mol F2 --------- 1 molecule F2
How many moles of molecules are there in 38g of fluorine F2?
To calculate the number of moles of F2 molecules in 38g, we first need to determine the molar mass of F2, which is 38 grams/mol. Next, we can use the formula: moles = mass / molar mass. Therefore, the number of moles in 38g of F2 is 1 mole.
How many moles in 1.5 x 1023 atoms of fluorine?
0,25 moles F2
How many grams of F2 are there in 1.73 mols of F2?
There are 53.4 grams of F2 in 1.73 moles of F2. This is calculated using the molar mass of fluorine (F2) which is 37.9968 g/mol.
A mixture containing 9 mol of F2 and 4 mol of S is allowed to react. How many moles of F2 remain after 3 mol of S have reacted?
After 3 moles of S have reacted, 3 moles of F2 will also have reacted since the reaction ratio is 1:1 based on the balanced chemical equation. This leaves 6 moles of F2 remaining (9 moles initially - 3 moles reacted).
5f2 2nh3 yields n2f4 6hf if you have 69.3 g nh3 how many grams of f2 are required for complete reaction?
To find the grams of F2 required for the reaction, first calculate moles of NH3: 69.3 g NH3 / 17.03 g/mol = 4.07 moles NH3. From the balanced equation, 5 moles of NH3 react with 2 moles of F2, so you need 4.07 moles NH3 * (2 moles F2 / 5 moles NH3) * 38.0 g/mol = 30.6 g of F2 for complete reaction.
What is the coefficient for F2 in Ca plus F2 CaF2?
The coefficient for F2 in the chemical equation Ca + F2 → CaF2 is 1.
The partial pressure of F2 in a mixture of gases where the total pressure is 1atm is 300 torr what is the mole fraction of F2?
0.395 total moles moles F 760.torr 300.torr total moles moles F 2 2 = ×
How many moles are in 45g of F?
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
How many liters of fluorine gas will it take to convert 100 grams of C2H4 to C2H4F2 using the following reaction?
The balanced reaction for converting 1 mol of C2H4 to C2H4F2 using F2 gas is: C2H4 + 2 F2 -> C2H4F2 First, calculate the moles of C2H4 in 100g. Then, using the mole ratio from the balanced equation, determine how many moles of F2 are needed. Finally, convert the moles of F2 to liters using the ideal gas law (PV = nRT) at the given conditions.
Determine the volume of 76g of f2 at stp?
To find the volume of 76g of F2 at STP, we first need to determine the number of moles of F2 using the molar mass. The molar mass of F2 is 38 g/mol. 76g / 38 g/mol = 2 moles of F2. At STP, 1 mole of any gas occupies 22.4 L. Therefore, 2 moles of F2 would occupy 44.8 L at STP.
