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2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine

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7y ago
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13y ago

5.54 grams F2 (1mole F2/38 grams)(6.022 X 10^23/1mole F2)

= 8.78 X 10^22 atoms of F2

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14y ago

.07986 moles

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Q: How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
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