2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
5.54 grams F2 (1mole F2/38 grams)(6.022 X 10^23/1mole F2)
= 8.78 X 10^22 atoms of F2
.07986 moles
850,49 g of NF3 = 11,9784 moles
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
There is 19g of fluorine. That makes 1 mole.
Roughly 3.123 liters (at the same pressure). Nitrogen is 78.08% of dry air by volume. 3.123 liters of nitrogen at STP is about 0.14 moles, or just under 2 grams.
.298 Moles
The answer is 24,92 g nitrogen.
850,49 g of NF3 = 11,9784 moles
31.4
137g
1,8 grams of fluorine is equivalent to 0,0947 moles.
25.9 grams fluorine (1 mole F/19.0 grams)(6.022 X 1023/1 mole F) = 8.21 X 1023 atoms of fluorine ======================
15 grams of nitrogen are equal to 1,071 moles.
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
There is 19g of fluorine. That makes 1 mole.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
Roughly 3.123 liters (at the same pressure). Nitrogen is 78.08% of dry air by volume. 3.123 liters of nitrogen at STP is about 0.14 moles, or just under 2 grams.
28 grams of Nitrogen is necessary to produce 34 grams of ammonia.