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How many moles of NF3 are in 850.49 grams of nitrogen trifluoride?
Wiki User
∙ 13y ago
850,49 g of NF3 = 11,9784 moles
Wiki User
∙ 13y ago
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How many moles are there in 10.0 of nitrogen dioxide?
10 grams NO2 (1 mole NO2/46.01 grams) = 0.217 moles nitrogen dioxide ======================
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
What is the percent of nitrogen in 4.444 moles of ammonium sulfide?
It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide
How many moles of NH3 can be produced from 14 grams of N2?
The molecular mass of NH3 is the sum of the atomic mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
How many moles of ammonia are needed to produce 3.5 mole of nitrogen?
That amount of ammonia contains two moles of hydrogen gas. One mole of hydrogen gas weighs 2.016 grams. Therfore 3.75 grams of ammonia contains two moles of hydrogen.
How many grams of nitrogen are present in 1.78 moles of nitrogen trifluoride?
The answer is 24,92 g nitrogen.
How many molecules of nitrogen trifluoride are present in 4.91 moles of nitrogen trifluoride?
4.91 mol * 6.02214129(27)×1023 / mol = 2.96 ×1024
How many moles of nitrogen are in 15 grams of nitrogen?
15 grams of nitrogen are equal to 1,071 moles.
How many moles of nitrogen are there in 29 grams of nitrogen?
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
How many moles of nitrogen are contained in a 35.0g sample?
35.0 moles nitrogen (1 mole N/14.01 grams) = 2.50 moles nitrogen ----------------------------
How many moles are there in 10.0 of nitrogen dioxide?
10 grams NO2 (1 mole NO2/46.01 grams) = 0.217 moles nitrogen dioxide ======================
How many moles of fluorine are present in 2.67 grams of nitrogen trifluoride moles?
2.67 g NF3 x 1 mole NF3/71 g NF3 x 3 mole F/mole NF3 = 0.113 moles Fluorine
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
molar weight of N = 14 grams/mole 35.7 grams/14 grams/mole = 2.55 moles
How many moles of molecules are in 550 grams of nitrogen dioxide?
550 g of nitrogen dioxide is equal to 11,94 moles.
How many moles of nitrogen in 42 grams of nitrogen?
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
How many moles of nitrogen are in 4.0 times 10 with the power of 2 of quinine?
The clarity of this question is not clear. I will assume grams and possibly moles as that number does not look like a number of atoms. Grams first, then moles. 4.0 X 102 grams quinine (1 moleC20H2N2O2/302.236 grams)(2 moles N/1 mole C20H2N2O2) = 2.6 moles nitrogen =============== Pretty much the same procedure if you meant moles just no dividing out a mass.
How many moles are in 75 grams of sulfur?
For this you need the atomic mass of He. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.75.0 grams He / (4.00 grams) = 18.8 moles He
