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The molecular mass of NH3 is the sum of the Atomic Mass of nitrogen and three times the atomic mass of hydrogen, or 14.007 + 3(1.008) = 17.031. Therefore, the number of moles of NH3 in 14.0 grams is 14.007/17.031 = 0.822. Since each molecule of N2 supplies two nitrogen atoms and each molecule of NH3 needs only one nitrogen atom, the number of moles of N2 needed is half the number of moles of NH3 formed = 0.411.
What else can I help you with?
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
How many grams of NH3 can be produced from 4.10 moles of N and excess H?
There is no compound NH. However, there is ammonia, NH3. The reactants are nitrogen gas, N2, and hydrogen gas, H2.Multiply moles N2 by the mole ratio from the balanced equation between NH3 and N2, so that NH3 is in the numerator. Then multiply by the molar mass of NH3, 17.031 g/mol.Balanced equation: N2 + 3H2 --> 2NH34.10 mol N2 x (2 mol NH3)/(1 mol N2) x (17.031 g NH3)/(1 mol NH3) = 140. g NH3 = 1.40 x 10^2 g NH3 rounded to three significant figures.
5f2 2nh3 yields n2f4 6hf if you have 69.3 g nh3 how many grams of f2 are required for complete reaction?
To find the grams of F2 required for the reaction, first calculate moles of NH3: 69.3 g NH3 / 17.03 g/mol = 4.07 moles NH3. From the balanced equation, 5 moles of NH3 react with 2 moles of F2, so you need 4.07 moles NH3 * (2 moles F2 / 5 moles NH3) * 38.0 g/mol = 30.6 g of F2 for complete reaction.
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
How many grams of NH3 can be produced from 2.79 moles of N2?
The mass of ammonia will be 95,03 g.
How many moles of NH3 are produced when 1.2 moles H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 moles of H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
If you have 3.64 g of H2 how many grams of NH3 can be produced?
To determine how many grams of NH3 can be produced from 3.64 g of H2, we first need to use the balanced chemical equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. The molar mass of H2 is approximately 2.02 g/mol, so 3.64 g of H2 is about 1.80 moles. According to the reaction, 3 moles of H2 produce 2 moles of NH3, so 1.80 moles of H2 would produce approximately 1.20 moles of NH3. The molar mass of NH3 is about 17.03 g/mol, resulting in about 20.4 grams of NH3 produced.
How many grams of NH3 can be produced from 2.08 grams of N2?
Ok, so I'm assuming that the chemical formula is written as - 3H2 + N2 ----> 2NH3 2.80 = moles of N2 17.03052 g/mol = Molar mass of NH3 (2.80 mol N2) x (2 NH3) / (1 N2) = 5.6 mol NH3 x (17.03052 g) / (1 mol NH3) = 95.4 g NH3
100 grams of ammonia equals how many moles?
For this you need the atomic (molecular) mass of NH3. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. NH3=16.0 grams100 grams NH3 / (16.0 grams) = 6.25 moles NH3
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of (NH4)2SO4 do you have?
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.
How many grams of NH3 can be produced from 4.46 mol of N2 and excess H2.?
The molecular weight of NH3 is 17.03-grams per mole and 14.01 for N2. The reaction is N2 + 3H2 = NH3. Therefore for every 1-mole of N2 as a reactant 1-mole of NH3 is produced. .2941-moles of NH3 is produced with a mass of 5.01-grams.
What mass of an NH3!can be made from 35.0 grams of N2?
To determine the mass of ammonia (NH3) that can be produced from 35.0 grams of nitrogen gas (N2), we first need to use the balanced chemical equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. The molar mass of N2 is approximately 28.02 g/mol, allowing us to calculate the number of moles of N2 in 35.0 grams as about 1.25 moles. Since 1 mole of N2 produces 2 moles of NH3, 1.25 moles of N2 will yield 2.5 moles of NH3. The molar mass of NH3 is about 17.03 g/mol, so 2.5 moles of NH3 corresponds to approximately 42.58 grams.
