0
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
What else can I help you with?
How many moles of NH3 are produced when 1.2 moles H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of nh3 are produced from 1.5 moles h2?
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many moles of NH3 are produced when 1.2 moles H2 reacts?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of H2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
How many moles of NH3 are produced when 1.4 moles H2 reacts?
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
How many moles of NH3 can be produced from the reaction of 75g of N2?
0,044 moles of NH3 can be produced.
How many moles of nh3 are produced when 1.8 moles h2 reacts?
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 -> 2NH3 From the balanced equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, 1.8 moles of H2 will produce 1.2 moles of NH3.
How many moles of N2 reacted if 0.60 mol of NH3 is produced?
0,3 moles of nitrogen reacted.
If 5.0 moles of NH3 are produce how many moles of N2 must have been used?
If 5.0 moles of NH3 are produced 2.5 moles of N2 are used.
How many moles of nh3 are produced from 1.5 moles h2?
The balanced chemical equation for the reaction is: 3H2 + N2 -> 2NH3 From the stoichiometry of the balanced equation, 3 moles of H2 produces 2 moles of NH3. Therefore, if you have 1.5 moles of H2, you will produce 1.5 moles * (2 moles NH3 / 3 moles H2) = 1 mole of NH3.
How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?
The reaction would be H2 + 3N2 ==>2NH3moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 producedMolecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules
How many molecules (not moles) of NH3 are produced from 1.57104 g of H2?
The answer is 1,57.10e27 molecules.
How many moles of NH3 can be produced from 12.0mol of H2 and excess N2?
8 mol
How many molecules -not moles- of NH3 are produced from 3.07104 g of H2?
Balanced equation is N2 + 3H2 ==> 2NH33.07104 g H2 x 1 mol/1.0079 g = 1.7679 moles H2 presentmoles NH3 produced = 2/3 x 1.7679 moles = 1.1786 moles NH3 formedmolecules NH3 = 1.1786 moles x 6.022x10^23 molecules/mole = 7.098x10^23 molecules (4 sig figs based on sig figs used in 6.022x10^23)
