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How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
What is the percent of nitrogen in ammonium sulfate?
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
What is the amount of nitrogen in ammonium chloride?
about 24.99% nitrogen is present in ammonium chloride........
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
What is the percent of nitrogen in ammonium sulfate?
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
How many grams of nitrogen and phosphorus are available in 1.00 pound of ammonium phosphate?
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
When 500g of ammonia reacted with excess sulfuric acid to produce ammonium sulfate 1789g of product were obtained What is the percent yield of ammonium sulfate for this reaction?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
What is the mass of 0.45 mol of ammonium sulfate?
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
How many grams of nitrogen are present in 1.78 moles of nitrogen trifluoride?
The answer is 24,92 g nitrogen.
