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What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
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∙ 11y ago
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∙ 11y ago
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How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
744 g/L of ammonium sulphate, at 20 0C
What is the percent of nitrogen in ammonium sulfate?
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The weight is 132.15 g.
How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?
5.50
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
How many grams per liter ammonium sulfate are in a saturated solution of ammonium sulfate?
744 g/L of ammonium sulphate, at 20 0C
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
What is the percent of nitrogen in ammonium sulfate?
The chemical formula of Ammonium sulfate is (NH4)2SO4. The first step to these problems is finding all the atomic weights of the elements involved (including how many atoms of each element there is) and then adding them all up to get the total molecular mass of ammonium sulfate.Nitrogen = 14.0 × 2 = 28.0 gramsHydrogen = 1.00 × 8 = 8.00 gramsSulfur = 32.1 gramsOxygen = 16.0 × 4 = 64.0 grams-------------------------------------------Ammonium sulfate = 132.1 gramsThen to figure out the percentage of nitrogen in the compound, take the total mass of nitrogen and divide it by the total mass.Mass of nitrogen ÷ mass of ammonium sulfate = % nitrogen28.0 ÷ 132.1 = .212 = 21.2% nitrogen in ammonium sulfate(NH4)2SO4Percentage nitrogen by mass=(Molar mass of nitrogen)/(Molar mass of ammonium sulfate)*100In ammonium sulfate there are 2 Nitrogens, 8 Hydrogens, 4 Oxygens and 1 Sulfur, and their molar masses are 14, 1, 16 and 32 respectively. So, by dividing the molar mass of nitrogen in the compound by the total molar mass of the compound and multiplying it by one hundred we get the percentage of nitrogen.(14*2)/(14*2+1*8+16*4+32)*100= 21.2121...=21%
What is the weight in grams of 1 mole of ammonium sulfate?
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
How many grams of nitrogen and phosphorus are available in 1.00 pound of ammonium phosphate?
There is said to be about 600 grams of nitrogen in 1.00 pound of ammonium and 130 pounds of phosphorus available in 1.00 pounds of ammonium phosphate.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The weight is 132.15 g.
How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?
5.50
How many grams of nitrogen are in 48.5g ammonium nitrate?
Ammonium Nitrate = NH4NO3 or N2H4O3 the total mass of a ammonium nitrate molecule is as follows: 2*14u + 4*1u + 3*16u = 28u + 4u + 48u = 80u now, the total mass of Nitrogen in one ammonium nitrate is 2*14u = 28u. Then, we divide 28 (the mass of Nitrogen) by 80 (total mass)= 28/80 = 0.35, which is the ratio for Nitrogen mass divided by total mass. then, we get the 48.5 grams (total mass) and multiply it by this ratio (0.35): 48.5 * 0.35 = 16.975 grams of Nitrogen in 48.5 grams of Ammonium Nitrate.
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
1.5 moles
What is the percent of nitrogen in 4.444 moles of ammonium sulfide?
It is important to know that the percent of nitrogen in 4.444 moles of ammonium sulfide is the same as the percent of nitrogen in 454 grams or 4843 moles or 96 kg, etc. Remember the law of definite proportions - chemical compounds always contain the same proportion of elements by mass. Perhaps you were asking how much nitrogen is in 4.444 moles of ammonium sulfide given the percent of nitrogen in any given mass. So we'll do that too: find the percent of nitrogen in any given sample and apply it specifically to 4.444 moles.Before we go directly to the 4.444 moles, we have to figure out how much nitrogen is in any amount of ammonium sulfide by percent. To do this, we need the atomic weights of the elements and add them up to find the total molar mass of the compound.Ammonium sulfide = (NH4)2SNitrogen = 14.0 grams × 2 = 28.0 gramsHydrogen = 1.01 grams × 8 = 8.08 gramsSulfur = 32.1 grams------------------------------------------------------Ammonium sulfide = 68.2 gramsNow we take the mass of nitrogen and divide it by the total mass to get our percent.Nitrogen ÷ Ammonium sulfide = % Nitrogen28.0 grams ÷ 68.2 grams = 0.411 = 41.1% Nitrogen in Ammonium sulfideSince we know that in any amount of Ammonium sulfide contains 41.1% of Nitrogen, we can apply it to the mass given.41.1% of 4.444 moles = .411 × 4.444 = 1.83 moles of Nitrogen in 4.444 moles Ammonium sulfide
400.0 grams of ammonia react with 56.0 moles of sulfuric acid to produce ammonium sulfate?
44.1-44.5 -Apex
