The molar mass of ammonium sulfate is 132,14 g.
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
about 24.99% nitrogen is present in ammonium chloride........
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
Use the compbined equation mass(g) / Mr = [conc] x vol(mL) / 1000 ( = moles) Algebraically rearrange mass(g) = Mr X [conc] x vol(mL)/1000 Substituting mass(g) = 132.1 x 8Mol/L x 1500 mL/ 1000 = 1585.2 g or 1.5852 kg NB The '1000' is used to convert the units of L(itres) in 'M' to mL.
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
Approximately 770 grams of ammonium sulfate can dissolve in one liter of water to form a saturated solution at room temperature.
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
about 24.99% nitrogen is present in ammonium chloride........
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
The theoretical yield of ammonium sulfate can be calculated by determining the amount that would be produced if all the ammonia reacted. Given that 500g of ammonia was used, convert this amount to grams of ammonium sulfate. Then, divide the actual yield (1789g) by the theoretical yield and multiply by 100 to calculate the percent yield.
To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.
There are 2.42 grams of sodium in 10 grams of sodium sulfate (Na2SO4). This is calculated based on the molecular weight of sodium sulfate and the molar ratio of sodium to the sulfate ion in the compound.
159.61 grams per mole.
0.758 moles of NH3 is the amount of moles in 50 grams of NH42SO4.