3.23
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
When sodium sulfate (Na2SO4) dissolves in water, it dissociates into two sodium ions (2Na+) and one sulfate ion (SO4^2-), totaling three ions in solution.
Sodium sulfate (Na2SO4) contains 4 elements: sodium (Na), sulfur (S), and oxygen (O).
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
Sodium sulfate is not prepared from hydrogen chloride.
41,1 g of sodium sulfate (Na2SO4, anhydrous) contain 10,455.10e23 atoms.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
The formula for sodium sulfate is Na2SO4. Therefore, there are 2 sodium atoms, one sulfur atom, and 4 oxygen atoms, for a total of 7.
In one molecule of sodium sulfate, there are 2 sodium atoms (Na), 1 sulfur atom (S), and 4 oxygen atoms (O).
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
When sodium sulfate (Na2SO4) dissolves in water, it dissociates into two sodium ions (2Na+) and one sulfate ion (SO4^2-), totaling three ions in solution.