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How many grams of sodium are there in 10 g of sodium sulfate Na2SO4?
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How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
Na2SO4 is a typical ionic sulfate containing how many Na ions and SO42- ions?
Sodium is the cation (+1 charge), sulfate is the anion (-2 charge) The chemical formula tells us there are two sodium ions (Na2) and one sulfate (SO4) ion.
How many grams of sodium are in 0.820 moles of Na2SO4?
na2so4= 142.05 g/mole, use dimensional analysis & set up your problem 13.64g
How many atoms does sodium sulfide have?
Sodium Sulfate is Na2SO4 and so there are 7 atoms in the molecule.
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?
How many grams of sodium are there in 10.0 grams of sodium sulfate?
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
How many grams are in 3.6 moles of sodium sulfate?
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
How many grams of sodium sulfate will be formed if you start with 12.5 grams of sodium hydroxide and you have an excess of sulfuric acid?
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
How many grams of HCl are needed to make 21.5 grams of Na2SO4?
Sodium sulfate is not prepared from hydrogen chloride.
How many atoms are there in 41.1 g of sodium sulfate (Na2SO4)?
41,1 g of sodium sulfate (Na2SO4, anhydrous) contain 10,455.10e23 atoms.
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
How many moles of atoms are contained in 2.88g na2 so4?
Full formal set up. 2.88 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(6.022 X 1023/1 mole Na2SO4)(1 mole Na2SO4 atoms/6.022 X 1023) = 0.020 moles of sodium sulfate atoms ------------------------------------------------------( you can see the last two steps are superfluous )
How many atoms are represented in one unit of sodium sulfate?
The formula for sodium sulfate is Na2SO4. Therefore, there are 2 sodium atoms, one sulfur atom, and 4 oxygen atoms, for a total of 7.
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?
The answer is approx. 2 moles (for anhydrous sodium sulfate).
How many grams of solid barium sulfate form when 22.6 mL of 0.160 M barium chloride reacts with 54.6 mL of 0.055 M sodium sulfate?
Balanced equation first. BaCl2 + Na2SO4 -> 2NaCl + BaSO4 22.6 ml BaCl2 = 0.0226 liters 54.6 ml Na2SO4 = 0.0546 liters 0.160 M BaCl2 = moles BaCl2/0.0226 liters = 0.00362 moles BaCl2 0.055 M Na2SO4 = moles Na2SO4/0.0546 liters = 0.0030 moles Na2SO4 The ratio of BaCl2 to Na2SO4 is one to one, so either mole count wull drive this reaction. Use 0.0003 moles Na2SO4 0.0030 moles Na2SO4 (1 mole BaSO4/1 mole Na2SO4)(233.37 grams/1 mole BaSO4) = 0.700 grams of BaCO4 produced
