3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4)
= 511.38 grams Na2SO4
==================( you do significant figures )
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
55.0 moles of sodium are equal to 1 264,44 g.
22.98977 grams.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
There are 2.42 grams of sodium in 10 grams of sodium sulfate (Na2SO4). This is calculated based on the molecular weight of sodium sulfate and the molar ratio of sodium to the sulfate ion in the compound.
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
25,3 moles of potassium sulfate hva a mass of 4,4409 kg.
23.3772 grams are there in four tenths moles of sodium chloride
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
The molar mass of sodium hydrogen carbonate is 84 grams per mole, therefore 0.5 moles of it weighs 42 grams.
55.0 moles of sodium are equal to 1 264,44 g.
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.