2
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
5,7 moles (SO4)3-.
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
The answer is approx. 2 moles (for anhydrous sodium sulfate).
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.