0
What else can I help you with?
How many moles of sodium sulfate are in 0.1000g of the compound?
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
HOW many moles are in 4.5 moles of sodium fluoride?
There are 4.5 moles of sodium fluoride in 4.5 moles of sodium fluoride.
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
If 2 moles of sodium sulfate are dissolved in water how many moles of ions are in solution a- 2 b- 3 c- 6 d- 15?
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.
How many moles of sodium sulfate are in 0.1000g of the compound?
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
How many moles of sulfate ions SO4 are present in 1.9 moles Al2 SO43?
5,7 moles (SO4)3-.
How many moles of sulfate ions (SO42) are present in 1.7 moles of Al2(SO4)3?
There are 3 moles of sulfate ions (SO4^2-) present in 1 mole of Al2(SO4)3. Therefore, in 1.7 moles of Al2(SO4)3, there would be 3 * 1.7 = 5.1 moles of sulfate ions.
How many atoms of sodium are present in Moles of sodium and what is the mass of it?
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?
The answer is approx. 2 moles (for anhydrous sodium sulfate).
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
