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How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
In the formula for sodium phosphate Na3PO4 how many moles of sodium are represented?
There are 3 moles of sodium represented in one mole of sodium phosphate (Na3PO4). This is because the subscript 3 in Na3PO4 indicates that there are 3 sodium ions for every molecule of sodium phosphate.
How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
If 2 moles of sodium sulfate are dissolved in water how many moles of ions are in solution a- 2 b- 3 c- 6 d- 15?
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.
Mass in grams if the molar mass of sodium sulfate is 141.98 gramsmoles?
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?
Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.
What is the equivalent weight of sodium sulfate?
The equivalent weight of sodium sulfate is 142 g/mol. This value is calculated by taking the molar mass of sodium sulfate (142 g/mol) and dividing it by the number of equivalents of the compound (2 equivalents, as each formula unit can donate 2 moles of charge during a reaction).
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
How many Na2SO4 molecules are present in 1.125 moles?
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
How many moles are there in 8.50 Molecules or sodium sulfate?
To convert molecules to moles, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, to find the number of moles in 8.50 molecules of sodium sulfate, you calculate ( \frac{8.50 \text{ molecules}}{6.022 \times 10^{23} \text{ molecules/mole}} ), which gives approximately (1.41 \times 10^{-23}) moles of sodium sulfate.
How many sodium ions are there in .482 mole of sodium sulfate Na2SO4?
There are 2 moles of sodium ions in 1 mole of sodium sulfate (Na2SO4). Therefore, in 0.482 moles of sodium sulfate, there would be 0.482 x 2 = 0.964 moles of sodium ions. Finally, multiplying by Avogadro's number (6.022 x 10^23) gives approximately 5.80 x 10^23 sodium ions.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
