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Q: How many moles of sodium sulfate are in 0.1000g of the compound?
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When 0.5 moles of Na2SO4 is dissolved in water how many moles of sodium ions are present?

Since the formula shows two sodium atoms in each formula unit of sodium sulfate and this compound normally completely ionizes in water solution, the number of sodium ions will be twice the number of moles of the salt; in this instance, 1.0 moles of sodium ions.


How many moles of sodium sulfate are present in 284 g?

2


How many MOLES of sodium nitrate are present in 2.85 grams of this compound?

How many MOLES of sodium nitrate are present in 2.85 grams of this compound ?


How many Na2SO4 molecules are present in 1.125 moles?

1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.


In the formula for sodium phosphate Na3PO4 how many moles of sodium are represented?

the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...


What is the mass in grams of 0.150 mol of sodium sulfate?

Sodium Sulfate is Na2SO4 and the molecular weight is 142. So 0.15 moles would have a mass of 0.15 x142 = 21.3g.


How many moles of solute are present in 1.5 liters of 1.33 M of Na2SO4?

The answer is approx. 2 moles (for anhydrous sodium sulfate).


What is table salt compound?

Table salt is mainly sodium chloride - a compound with equal parts (in atoms or moles) of sodium and chlorine.


The hydrate sodium sulfate on heating the hydrate how many moles of water should be driven off per mole of hydrate?

The answer is 10 moles water.


The hydrate of sodium sulfate on heating the hydrate how many moles of water should be driven off per mole of hydrate?

The answer is 10 moles water.


On heating the hydrate how many moles of water should be driven off per mole of hydrate of sodium sulfate?

10 moles of water are released.


How many moles of sodium chloride (NaCl) are in 79.9 g of the compound?

79,9 g NaCl is equivalent to 1,367 moles.The formula mass of the compound sodium chloride, NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 79.9/58.5 = 1.37molThere are 1.37 moles of sodium chloride in a 79.9 gram pure sample of the compound.