Yes, the molar mass of anhydrous sodium sulfate is 142,035 grams.
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
The mass in grams of 1,40 mol of anhydrous iron(III) sulfate is 559,832.
How many grams of Na+ are contained in 25 g of sodium sulfate (Na2SO4)?
3.23
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
Balanced equation. 2NaOH + H2SO4 -> Na2SO4 + 2H2O 12.5 grams NaOH (1 mole NaOH/39.998 grams)(1 mole Na2SO4/2 mole NaOH)(142.05 grams/1 mole Na2SO4) = 22.2 grams sodium sulfate produced ===========================
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
Sodium sulfate is not prepared from hydrogen chloride.
Sodium Sulfate is Na2SO4 and the molecular weight is 142. So 0.15 moles would have a mass of 0.15 x142 = 21.3g.
One liter of Benedict's solution contains 173 grams sodium citrate, 100 grams sodium carbonate, and 17.3 grams cupric sulfate pentahydrate.
3.6 moles N2SO4 (142.05 grams/1 mole Na2SO4) = 511.38 grams Na2SO4 ==================( you do significant figures )
The gram formula mass of anhydrous sodium sulfate is 142.04. Therefore, 43 gram formula units* of it has a mass of 43(142.04)6.1 X 103 grams, to the justified number of significant digits. _____________________________ For ionic compounds such as sodium sulfate, the term "formula unit" is preferred to "mole".
Aluminium Sulphate is Al2(SO4)3 and its mass is27x2 + 96x3 = 342g/mole
211 is the mass in grams of 1.15 moles of strontium sulfate.