The gram formula mass of anhydrous sodium sulfate is 142.04. Therefore, 43 gram formula units* of it has a mass of 43(142.04)6.1 X 103 grams, to the justified number of significant digits.
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For ionic compounds such as sodium sulfate, the term "formula unit" is preferred to "mole".
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
To find the mass of sodium sulfate, we need to know the molar mass of Na2SO4, which is about 142.04 g/mol. Multiply the number of moles by the molar mass to get the mass: 0.150 mol * 142.04 g/mol = 21.31 grams. So, the mass of 0.150 mol of sodium sulfate is 21.31 grams.
No, the mass is conserved.
To find the number of moles of sodium sulfate in 0.1000g of the compound, you first need to determine the molar mass of Na2SO4. Then, divide the given mass by the molar mass to get the moles.
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
No, sodium laureth sulfate and sodium lauryl sulfate are not the same. Sodium laureth sulfate is a milder surfactant compared to sodium lauryl sulfate, which can be harsher on the skin.
The solubility of sodium sulfate in water at 30°C is approximately 49.7 g/100 g of water. Since you have 250 g of water, you can dissolve approximately 124.25 g of sodium sulfate in it at that temperature.
The milligram equivalent weight of sodium sulfate (Na₂SO₄) can be calculated by determining its molar mass and the number of moles of reactive species it provides. The molar mass of sodium sulfate is approximately 142.04 g/mol. Since it dissociates into two sodium ions (Na⁺) and one sulfate ion (SO₄²⁻), the equivalent weight for sodium sulfate in terms of sulfate ions is 71.02 mg/equiv. This value corresponds to the sulfate ion's contribution, as it provides two equivalents of charge per mole.
No, sodium lauryl sulfate and sodium laureth sulfate are not the same. Sodium lauryl sulfate is a harsher cleansing agent, while sodium laureth sulfate is milder and less irritating to the skin.
55.91% The mass of NaSo4 is 142.05 plus the mass of 10 H2O molecules (180.16) is 332.21. Divide the mass o water overthe total mass to get .5591 or 55.91%
Anhydrous sodium sulfate has a molar mass of (23+23+32+16+16+16+16) = 142.