0
What else can I help you with?
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The molar mass of aluminum sulfate?
The molar mass of aluminum sulfate, Al2(SO4)3, can be calculated by adding together the atomic masses of all the elements in the compound. Aluminum has a molar mass of 26.98 g/mol, sulfur has a molar mass of 32.06 g/mol, and oxygen has a molar mass of 16.00 g/mol. By calculating the total molar mass, the molar mass of aluminum sulfate is found to be approximately 342.14 g/mol.
Mass in grams if the molar mass of sodium sulfate is 141.98 gramsmoles?
To calculate the mass in grams of sodium sulfate, we need to know the number of moles. Once we have the number of moles, we can multiply it by the molar mass to find the mass in grams. For example, if we have 2 moles of sodium sulfate, the mass would be 2 moles * 141.98 grams/mole = 283.96 grams.
How many grams of sodium sulfate are required to prepare a 350 mL solution whose concentration is 0.683 M?
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
How many grams of sodium sulfate Na's must be added to make 500 ml of M sodium sulfate solution?
To determine the grams of sodium sulfate needed, you first need to specify the molarity (M) of the sodium sulfate solution. Once you have the molarity, you can use the formula: grams = molarity (M) x volume (L) x molar mass (g/mol). This will give you the amount of sodium sulfate in grams needed to make the solution.
What is the mass of 43mol of sodium sulfate?
The gram formula mass of anhydrous sodium sulfate is 142.04. Therefore, 43 gram formula units* of it has a mass of 43(142.04)6.1 X 103 grams, to the justified number of significant digits. _____________________________ For ionic compounds such as sodium sulfate, the term "formula unit" is preferred to "mole".
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many moles of sodium sulfate are present in 0.1000 grams of the compound?
To determine the number of moles of sodium sulfate in 0.1000 grams of the compound, you would first need to calculate the molar mass of sodium sulfate (Na2SO4), which is 142.04 g/mol. Then, you would divide the given mass by the molar mass to find the number of moles: 0.1000 g / 142.04 g/mol ≈ 0.0007 moles of sodium sulfate.
How many moles of sodium sulfate are present in 284 g?
To find the number of moles of sodium sulfate in 284 g, you need to divide the given mass by the molar mass of sodium sulfate. The molar mass of sodium sulfate (Na2SO4) is 142 g/mol. So, 284 g / 142 g/mol = 2 moles of sodium sulfate.
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.
What is the mass in grams of 1.15 mol of strontium sulfate?
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
How many grams are in one mole of sulfate?
The molar mass of sulfate is 96.06 g/mol. Therefore, one mole of sulfate contains 96.06 grams of sulfate.
How many grams of Na+are contained in 25 g of sodium sulfate (Na2SO4)?
To find the mass of Na+ in sodium sulfate (Na2SO4), we need to consider the molar ratios of Na+ in the compound. In Na2SO4, there are 2 Na+ ions for every 1 Na2SO4 unit. The molar mass of Na2SO4 is 142 g/mol, so in 25 g of Na2SO4, there are about 8.8 g of Na+.
The molar mass of aluminum sulfate?
The molar mass of aluminum sulfate, Al2(SO4)3, can be calculated by adding together the atomic masses of all the elements in the compound. Aluminum has a molar mass of 26.98 g/mol, sulfur has a molar mass of 32.06 g/mol, and oxygen has a molar mass of 16.00 g/mol. By calculating the total molar mass, the molar mass of aluminum sulfate is found to be approximately 342.14 g/mol.
