22.98977 grams.
4.2 teaspoons are present in 21 grams of cappucino
21 grams is about 0.740753201 ounces, or just a bit short of 3/4ths of an ounce. Here's the formula: 21 g* 1 oz 28.34952313 g = 0.7407532009 oz
21 grams (per the nutritional information label I have in front of me) This depends on the density of honey.
To find the number of grams of substance needed, you'll need to consider the ideal gas law, which is PV = nRT. Here are the steps: Calculate the amount of substance (n) using the ideal gas law: n = (PV) / (RT) Convert moles to grams using the molar mass of the substance. Substitute the given values into the equation: P = 815 atm, V = 53.0 L, T = 21 degrees Celsius (294 K), and R = 0.0821 L·atm/(K·mol) for gases. Solve for n and then convert moles to grams.
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3 0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21 1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions 3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl The formula to solve this problem appears above.
4.828gNa X (1 mole/22.989gNa) = .21 22.989 = atomic weight of Na
1.56 X 10^21 atoms of sodium ( 1 mole Na/6.022 X 10^23) = 0.00259 moles sodium or 2.59 X 10^-3 moles sodium
To find the mass of fluorine produced, first calculate the mass of sodium fluoride: 27.7 grams of sodium / (1 part sodium / 1 part sodium fluoride) = 27.7 grams of sodium fluoride Now, since the ratio of sodium to fluorine in sodium fluoride is 1:2 (1 part sodium to 2 parts fluorine), the mass of fluorine is 27.7 grams / 2 = 13.85 grams.
Sodium has an atomic mass of 29.990 g/mol. This means that 124 sodium atoms have a mass of 3718.76 amu, if the isotopes follow the average. To find in grams, the following must be used: 124 sodium atoms equal 2.0598 * 10-22 moles, so 124 sodium atoms have a mass of 6.177 *10-21 grams.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
Since the reaction involves the formation of sodium chloride (NaCl), the molar ratio of sodium to chlorine is 1:1. Therefore, if 10 grams of sodium reacts to form 35 grams of NaCl, then 35 grams of chlorine is also needed for this reaction.
21 ounces = 595.34 grams.
21 ounces = 595.34 grams.
1 gram = 10 decigrams so 21 grams = 21*10 = 210 grams. Simple!
See the Related Questions to the left to solve this problem.
4.2 teaspoons are present in 21 grams of cappucino
To convert from molecules to moles, you divide the number of molecules by Avogadro's number (6.022 x 10^23). So, for 4.3 x 10^21 molecules of UF6, you would have approximately 0.0071 moles of UF6.