0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3
0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21
1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions
3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl
The formula to solve this problem appears above.
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
The mass of sulfuric acid is 490,395 grams.
The answer is 699 moles perchloric acid.
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
The molecular formula for carbonic acid is H2CO3. To find the mass of carbonic acid formed, first calculate the moles of carbon and water. Then, determine the limiting reactant and use it to calculate the moles of carbonic acid formed. Finally, convert the moles of carbonic acid to grams to find the mass.
The balanced chemical equation for aluminum reacting with hydrochloric acid is: 2Al(s) + 6HCl(aq) -> 2AlCl3(aq) + 3H2(g) This equation shows that two moles of aluminum react with six moles of hydrochloric acid to produce two moles of aluminum chloride and three moles of hydrogen gas.
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
The mass of hydrochloric acid needed to react with 87.7 grams of aluminum can be calculated using stoichiometry. The balanced chemical equation for the reaction between hydrochloric acid (HCl) and aluminum (Al) is 2Al + 6HCl → 2AlCl3 + 3H2. By applying stoichiometry, you'll find that the molar mass ratio between Al and HCl is 1:6. Therefore, the amount of HCl needed to react with 87.7 grams of Al is: (87.7 grams Al) x (6 moles HCl / 1 mole Al) x (36.46 g HCl / 1 mole HCl) = 151.63 grams of HCl.
To determine the maximum mass of nitric acid required to react with 0.35 grams of copper metal, we need to calculate the moles of copper using its molar mass. Then, we use the balanced chemical equation between copper and nitric acid to find the mole ratio between them. Finally, we convert the moles of copper to moles of nitric acid and then to grams. The maximum mass of nitric acid needed can be determined as per the stoichiometry of the balanced chemical equation.
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------
The balanced chemical equation for the reaction between sulfurous acid and aluminum hydroxide to form aluminum sulfite and water is: 3H2SO3 + 2Al(OH)3 → Al2(SO3)3 + 6H2O This equation shows that 3 moles of sulfurous acid and 2 moles of aluminum hydroxide react to produce 1 mole of aluminum sulfite and 6 moles of water.
Aluminum.
To determine the limiting reactant, we need to calculate the amount of each reactant in terms of the same unit (moles). Then, we compare the mole ratio of the reactants from the balanced chemical equation. In this case, convert 60.0 grams of aluminum to moles and 25 grams of hydrochloric acid to moles. Compare the moles of each reactant to determine the limiting reactant.
Hydrochloric acid can dissolve aluminum but not nickel. Aluminum forms a soluble aluminum chloride compound in hydrochloric acid, while nickel does not react with hydrochloric acid due to its passivation layer.