In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
The balanced chemical equation for the reaction is 1 mol of sulfuric acid reacts with 2 mol of ammonium hydroxide. Therefore, for 8 mol of ammonium hydroxide, 4 mol of sulfuric acid are needed. To calculate the grams of sulfuric acid needed, you would multiply the number of moles by the molar mass of sulfuric acid.
Sodium hydroxide is typically contaminated with sodium carbonate due to exposure to carbon dioxide in the air. Sodium hydroxide readily absorbs carbon dioxide, which can react with the sodium hydroxide to form sodium carbonate. This contamination can affect the purity and concentration of the sodium hydroxide solution.
There is no reaction. "Hydroxide acid" is water, which does not react with sodium hydroxide.
The reaction between sodium hydroxide and sulfuric acid produces sodium sulfate and water. Sodium hydroxide (NaOH) reacts with sulfuric acid (H2SO4) in a neutralization reaction to form sodium sulfate (Na2SO4) and water (H2O).
It makes sodiumchloride and water
Sulfuric acid reacts easily with sodium hydroxide to form sodium sulfate and water because sulfuric acid is a strong acid and sodium hydroxide is a strong base. This reaction occurs because both acids and bases react to form water and a salt. Hydrochloric acid may not react in the same way because it is a weaker acid compared to sulfuric acid.
To make sodium bisulfate, one can react sodium hydroxide with sulfuric acid. This reaction forms sodium bisulfate and water.
Na +H2O -> NaOH +(1/2)H2 Every mole of Sodium requires one mole of water to make one mole of Sodium Hydroxide. So two moles of Sodium will produce two moles of Sodium Hydroxide. If there are three moles of water in the initial reaction then there will be one mole of water left over after reacting with two moles of Sodium. This reaction will produce half a mole of hydrogen gas.
Yes, sodium hydroxide and sulfuric acid will react vigorously when mixed together. The reaction between them is highly exothermic, producing heat and generating steam. It is important to handle these chemicals with caution to prevent violent or dangerous reactions.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
When sodium hydroxide and sulfuric acid react, they form sodium sulfate and water. This is a neutralization reaction where the acidic and basic components combine to produce a salt and water.
The balanced equation for this reaction is: 2Na + 2H2O -> 2NaOH + H2. This means that two moles of sodium react with two moles of water to produce two moles of sodium hydroxide and one mole of hydrogen gas.
Sodium hydroxide and sodium sulfate don't actually react.
When 4 moles of sodium react with oxygen, 2 moles of sodium oxide are produced (according to the balanced equation). Therefore, when 10 moles of sodium react, 5 moles of sodium oxide will be produced.
Yes, sodium hydroxide can react with copper to form copper(II) hydroxide. When sodium hydroxide is added to a solution containing copper ions, a blue precipitate of copper(II) hydroxide is formed.