The compound copper (III) chloride doesn't exist !
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
You would write the balanced chemical equation as: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction involves the double displacement of ions between copper (II) chloride and sodium hydroxide to form copper (II) hydroxide and sodium chloride.
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
The balanced single replacement equation for iron and copper(II) chloride is: 2Fe + 3CuCl2 -> 2FeCl2 + 3Cu
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
You would write the balanced chemical equation as: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction involves the double displacement of ions between copper (II) chloride and sodium hydroxide to form copper (II) hydroxide and sodium chloride.
The balanced equation for the decomposition of copper (II) hydroxide is: Cu(OH)2(s) → CuO(s) + H2O(g)
CuCl
The balanced equation for copper(II) oxide and potassium chloride is CuO + 2KCl → CuCl2 + K2O When copper(II) oxide reacts with potassium chloride then it forms copper(II) chloride and potassium oxide.
The balanced single replacement equation for iron and copper(II) chloride is: 2Fe + 3CuCl2 -> 2FeCl2 + 3Cu
When copper(II) chloride reacts with sodium hydroxide, copper(II) hydroxide and sodium chloride are produced. The balanced chemical equation is: CuCl2 + 2NaOH -> Cu(OH)2 + 2NaCl. Copper hydroxide is initially formed as a blue precipitate which can further react to form black copper(II) oxide upon heating.
The balanced equation for Iron (III) chloride reacting with copper (II) sulfate is: 2FeCl3 + 3CuSO4 → Fe2(SO4)3 + 3CuCl2
The balanced equation for the reaction between copper(II) hydroxide (Cu(OH)2) and sulfuric acid (H2SO4) is Cu(OH)2 + H2SO4 → CuSO4 + 2H2O.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
Balanced equation: CuO + 2HCl --> CuCl2 + H2O Word equation: One mole of copper (II) oxide plus two moles of hydrochloric acid produces (or yields) one mole of copper (II) chloride plus one mole of water.