0
How many grams of sulfuric acid are needed to react with 8 mol of ammonium hydroxide?
Kmillz
2NH4OH + H2SO4 >> (NH4)2SO4 + 2H2O
8 moles NH4OH (1mol H2SO4/2mol NH4OH)(98.086g H2SO4/1mol H2SO4)
= 392.34 grams H2SO4 needed
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?
5.50
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
1.5 moles
How many grams of solid barium hydroxide are needed to exactly neutralize 14.7 mL of a 0.597 M perchloric acid solution?
How many grams of KHP are needed to exactly neutralize 36.7 mL of a 0.328 M barium hydroxidesolution
What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?
31.4
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
1
400.0 grams of ammonia react with 56.0 moles of sulfuric acid to produce ammonium sulfate?
44.1-44.5 -Apex
If there are 20 grams of NH3 dissolved in 100 grams of water at 30 degrees C. What type of solution will you have?
This is a homogeneous solution of ammonium hydroxide in water.
How many grams of ammonium carbonate would you need to make 2.10 liters of a 0.619 M solution?
124,9 g grams of ammonium carbonate are needed.
How many grams of water are needed to produce one hundred fifty grams of magnesium hydroxide?
A lot
How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?
5.50
How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?
1.5 moles
What is the answer and how did you get it using the balanced equation from problem 4 Determine the limiting reagent if you start with 200 grams of sodium hydroxide and 100 grams of sulfuric acid?
The chemical equation is:2 NaOH + H2SO4 = Na2SO4 + 2 H2OMolar mass of sodium hydroxide is 39,9971 g; molar mass of sulfuric acid is 98,079 g.2 . 39,9971 g NaOH----------------------98,079 g H2SO4200 g NaOH------------------------xx = (200 x 98,079)/2 . 39,9971 = 245 g H2SO4So sulfuric acid is the limiting reagent.
A volume of 40.0g of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid. What was the molarity of the solution if 25.7g of 1.50M was needed?
M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....
The formula for sulfuric acid is H2SO4 A mole of sulfuric acid would have a mass of grams?
It would be 98 grams.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
How many grams of sulfuric acid will neutralize 10.0 g of sodium hydroxide?
Balanced equation. H2SO4 + 2NaOH >> Na2SO4 + 2H2O 10 grams NaOH (1mol NaOH/39.998g )(1mol H2SO4/2mol NaOH )(98.086g H2SO4/1molH2SO4 ) = 12.26 grams of H2SO4
The formula for sulfuric acid is HËÃSOËÅ A mole of sulfuric acid would have a mass of grams?
It would have a mass of 98 grams.
