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I assume you mean excess hydrochloric acid. Balanced equation.

2Al + 6HCl = 2AlCl3 + 3H2

2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2)

= 0.303 grams hydrogen gas produced

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Q: What is the mass of hydrogen gas released from 2.70 g of aluminum metal and hydrochloric acid in grams?
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