I assume you mean excess hydrochloric acid. Balanced equation.
2Al + 6HCl = 2AlCl3 + 3H2
2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2)
= 0.303 grams hydrogen gas produced
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9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
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The answer is: approx. 327 g.
hydrochloric acid does not have an atomic number. Only elements have atomic numbers and hydrochloric acid is a compound composed of two non-metal elements: hydrogen and chlorine, as you might have guessed by the name. However: Hydrogen's atomic number is 1 and Chlorine's atomic number is 17
9g Al x (1 mol Al/27g Al) x (3mol H2 / 2 mol Al) x (22.4L / 1 mol H2) = 11.2L H2
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
How much is 5 grams of aluminum
17.9 grams
20,1588 grams of hydrogen
1,99 grams of aluminum is equal to 0,0737 moles.
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
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