0
How many grams of aluminum chloride can be made from 67.0 grams of aluminium and excess hydrochloric acid?
Wiki User
∙ 11y ago
The answer is: approx. 327 g.
Wiki User
∙ 11y ago
Add your answer:
Earn +20 pts
Why is aluminum chloride used in large excess in Friedel-Crafts reactions?
To ensure there's enough of it to allow the reaction to go to completion.
Name a salt which gives white precipitate on ammonium hydroxide solution and is insoluble in excess?
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
Why excess barium chloride is added to the filtrate in the preparation of a dry sample of barium sulphate?
Barium chloride in excess is added to be sure that the reaction is complete.
What is the substance remaining in the beaker after evaporaiting the excess acid of hydrochloric acid with manganese?
This compound is the manganese dichloride.
If you put excess iron III chloride in zinc what could be the products?
Go to your school lab and do it to find out. Let me know your results.
If you start with 3.52g aluminum and 5.03 g of chlorine with the the excess reactant and how much is in the excess?
We need 6,935 g aluminium; the excess of aluminium is 0,97 g.
The mass of calcium chloride formed when 2.5 g calcium cabonate are dissolved in excess of hydrochloric acid is?
Calcium chloride (CaCl2) resulted: 2,772 g.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
4 moles
Calculate the theoretical yield of calcium chloride expected for this reaction if 0.80 mol of calcium hydroxide is reacted with excess hydrochloric acid.?
0.80
You are given 34.0 g of aluminum and 39.0 g of chlorine gas. If you had excess chlorine how many moles of aluminum chloride could be produced from 34.0 g of aluminum?
1.26 mol of AlCl3
How many grams of aluminum chloride are produced when 18 grams of aluminum are reacted with an excess of hydrochloride acid?
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
Why is aluminum chloride used in large excess in Friedel-Crafts reactions?
To ensure there's enough of it to allow the reaction to go to completion.
What is the action of dilute hydrochloride on sodium carbonate?
Dilute hydrochloric acid? Carbon dioxide gas escapes and leaves sodium chloride solution, possibly leaving either an excess of acid, or an excess of sodium carbonate.
Name a salt which gives white precipitate on ammonium hydroxide solution and is insoluble in excess?
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
An excess of hydrochloric acid in the stomach causes indigestion.An indigestion tablet contains a mixture of calcium carbonate and magnesium hydroxide.Type a balanced chemical equation 4 the reaction.?
Caluim carbonate + Hydrochloric acid = Carcon dioxide + Calicum chloride + water
When 4 moles of aluminum are allowed to react with an excess of chlorine gas how many moles of aluminum chloride are produced?
Four:2 Al + 3 Cl2 --> 2 AlCl3so: 4 Al + 6 Cl2 --> 4 AlCl3
What is the reaction of aluminium chloride and ammonia?
The balance equation between aluminium chloride and ammonium hydroxide is given by: AlCl3 + 3NH4OH --> Al(OH)3 + 3NH4Cl However, in the case of excess NH4OH, ammonia does form, as with many metals, NH3 complexes and double salts. With Aluminium chloride, the double salt formed, which is apparently stable to 900 C, is AlCl3.6NH3. However, if you are a chemistry student or answering a question on an AP Chem exam, you might consider ignoring this part of the answer, as I doubt this knowledge is widely known. The reaction, with excess NH3, apparently proceeds at room temperature as: Al(OH)3 + 3 NH4Cl + 3 NH4OH --> AlCl3.6NH3 + 3 H2O
