To ensure there's enough of it to allow the reaction to go to completion.
The answer is: approx. 327 g.
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
Barium chloride in excess is added to be sure that the reaction is complete.
Go to your school lab and do it to find out. Let me know your results.
When exposed to air, calcium chloride can absorb moisture and become hydrated, forming a white, powdery substance. It is hygroscopic, meaning it has a strong affinity for water molecules in the air. This property allows calcium chloride to be used as a desiccant to remove excess moisture from the air.
4 moles
1.26 mol of AlCl3
The answer is: approx. 327 g.
The empirical formula for aluminum chloride is AlCl3, and its gram formula mass is 133.34. The formula shows that each formula unit contains one aluminum atom, and the the gram atomic mass of aluminum is 26.9815. Therefore, 18(133.34/26.9815) or 89 grams, to the justified number of significant digits, of aluminum chloride will be produced.
One such salt would be aluminum chloride since it is soluble but when reacted with ammonium hydroxide, the insoluble aluminum hydroxide forms a precipitate. Not sure what is meant by "is insoluble in excess", however.
Four:2 Al + 3 Cl2 --> 2 AlCl3so: 4 Al + 6 Cl2 --> 4 AlCl3
vomitting
Barium chloride in excess is added to be sure that the reaction is complete.
weakness and vomitting
If the addition of excess silver nitrate precipitates 8.07 g silver chloride, the concentration of chloride ion in 229 mL solution is .25.
yellow
Equation. 2Al + 3Cl2 -> 2AlCl3 one to one again 0.440 moles Al (2 moles AlCl3/2 moles Al) = 0.440 moles AlCl3 produced