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What is the limiting reactant of 60.0grams of aluminum present when a reaction with 25grams of hydrochloric acid occurs?
This reaction?
2Al + 6HCl -> 2AlCl3 + 3H2
Get moles species.
60.0 grams Al (1 mole Al/26.98 grams) = 2.2239 mole Al
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2.2239 moles Al (6 mole HCl/2 mole Al)
= 6.6717 moles HCl
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0.68572 moles HCl (2 mole Al/6 mole HCl)
= 0.22857 mole Al
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As you see you have way more moles aluminum than you need, but. you do not have nearly enough HCl to meet the mole burden.
Hydrochloric acid limits this reaction.
What else can I help you with?
If 0.25 g of Aluminum react with 0.6g of Copper sulfate then which one is the limiting reactant?
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
What is the limiting reactant in Mg plus HCl?
In the reaction between magnesium (Mg) and hydrochloric acid (HCl), the limiting reactant is the reactant that is consumed first, which determines the maximum amount of product that can be formed. To determine the limiting reactant, you would need to compare the moles of magnesium and hydrochloric acid to see which one is present in the lowest stoichiometric amount.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
If you had excess aluminum how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas Cl2?
To calculate the moles of aluminum chloride produced, you would first need to determine the limiting reactant. Compare the moles of each reactant (Aluminum and Cl2) using their molar masses. Whichever reactant produces fewer moles of aluminum chloride would be the limiting reactant. Once you have that, you can use the stoichiometry of the balanced chemical equation to calculate the moles of aluminum chloride produced.
What is the reactant called that gets used up first?
The Limiting Reactant is the reactant that runs out first in a reaction.
If 0.25 g of Aluminum react with 0.6g of Copper sulfate then which one is the limiting reactant?
To determine the limiting reactant, we need to compare the moles of each reactant. First, calculate the moles of aluminum and copper sulfate separately. Then, determine the mole ratio between them and see which reactant is present in lower amount compared to the stoichiometric ratio. The reactant that is present in lower moles is the limiting reactant.
What is the limiting reactant in Mg plus HCl?
In the reaction between magnesium (Mg) and hydrochloric acid (HCl), the limiting reactant is the reactant that is consumed first, which determines the maximum amount of product that can be formed. To determine the limiting reactant, you would need to compare the moles of magnesium and hydrochloric acid to see which one is present in the lowest stoichiometric amount.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How does the maximum yield of products for a reaction depend on the limiting reactant?
The best way to answer this question is with an example. Using Calcium oxide reacting with hydrochloric acid, the reaction formula is: CaO + 2HCl ----->CaCl2 + H2O The molecular weight for Calcium Oxide is 56, for Hydrochloric acid is 26.5 and for calcium chloride 110. If you start with only 56g of Calcium oxide but say 10000g of hydrochloric acid, the maximum yield of the product calcium chloride can only ever be 110g. It does not matter how much hydrochloric acid is added. The limiting reactant in this example is the calcium oxide.
If you had excess aluminum how many moles of aluminum chloride could be produced from 31.0 g of chlorine gas Cl2?
To calculate the moles of aluminum chloride produced, you would first need to determine the limiting reactant. Compare the moles of each reactant (Aluminum and Cl2) using their molar masses. Whichever reactant produces fewer moles of aluminum chloride would be the limiting reactant. Once you have that, you can use the stoichiometry of the balanced chemical equation to calculate the moles of aluminum chloride produced.
What is the reactant called that gets used up first?
The Limiting Reactant is the reactant that runs out first in a reaction.
What is the limiting reactant in alka-seltzer?
Sodium bicarbonate is the limiting reactant.
What is the maximum mass of aluminum chloride that can be formed when reacting 25.0 g of aluminum with 30.0 g of chlorine?
To find the limiting reactant, calculate the moles of each reactant using their molar masses. The balanced chemical equation is 2Al + 3Cl2 → 2AlCl3, so the stoichiometry ratio is 2:3. Aluminum is the limiting reactant as it forms fewer moles of product. Thus, all 25.0 g of aluminum will react with 112.5 g of chlorine to form 67.5 g of aluminum chloride.
Why is the theoretical yield of a reaction determined only by the amount of the limiting reactant?
The theoretical yield of a reaction is determined by the limiting reactant because this reactant is completely consumed in the reaction, and the amount of product that can be formed is limited by the amount of the limiting reactant available. Any excess of the other reactant does not contribute to the formation of additional product beyond what is possible with the limiting reactant.
If 5.433 g of aluminum is burned with 8.834 g of oxygen gas what is the limiting reactant?
Aluminium (Al) + Oxygen (O) = Aluminium Oxide (Al2O3)Aluminium Atomic weight = about 27Oxygen Atomic weight = about) 16Proportion in Al203 = Aluminium 54, Oxygen 48Thus the ratio of weight in Al2O3 is 54/48 = 1.125And the ratio present as reactants is 5.433/8.834 = 0.615Thus the Aluminium will run out before the Oxygen as the reaction proceeds, making the Aluminium the limiting reactant.
How many grams of aluminum oxide can you make if you have 100 grams of aluminum combining with 50 grams of oxygen?
To find the amount of aluminum oxide that can be made, we need to determine the limiting reactant. The balanced chemical equation for the reaction is 4Al + 3O2 → 2Al2O3. The molar mass of aluminum oxide is 101.96 g/mol. After determining the limiting reactant and doing the stoichiometry calculation, we find that 100 grams of aluminum can produce 197 grams of aluminum oxide in this reaction.
What is the limiting reactant when 3.14g of nitrogen react with 2.79g of hydrogen to produce ammonia and how many grams of ammonia are produce?
To determine the limiting reactant, we need to find the moles of each reactant. Then, we calculate the amount of ammonia that can be produced from each reactant. Whichever reactant produces the least amount of ammonia is the limiting reactant. Finally, we calculate the grams of ammonia produced based on the limiting reactant.
