HCl is the limiting reagent.
The first step is to determine the limiting reactant, which is the reactant that is used up first in the reaction. To do this, calculate the moles of each reactant using their molar masses. Then compare the mole ratio of the reactants to the stoichiometry of the reaction to find the limiting reactant. Once you have the limiting reactant, use its moles to calculate the theoretical yield of the product using the stoichiometry of the reaction.
The products of the reaction between magnesium (Mg) and hydrochloric acid (HCl) are magnesium chloride (MgCl2) and hydrogen gas (H2).
The molecular equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl) is: Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
Mg + 2HCl = MgCl2 + H2 SO magnesium chloride and Hydrogen gas
Assuming we are at standard temperature and pressure (STP), the answer is approximately 1.85L of hydrogen gas. The HCl is the limiting reactant and the Mg is the excess reactant.
The first step is to determine the limiting reactant, which is the reactant that is used up first in the reaction. To do this, calculate the moles of each reactant using their molar masses. Then compare the mole ratio of the reactants to the stoichiometry of the reaction to find the limiting reactant. Once you have the limiting reactant, use its moles to calculate the theoretical yield of the product using the stoichiometry of the reaction.
Mg + 2HCl = MgCl2 + H2
Moles Mg = 3.00 g / 24.312 g/mol =0.123 Moles O2 = 2.20 / 32 g/mol = 0.0688 2 Mg + O2 >> 2 MgO the ratio between Mg and O2 is 2 : 1 0.123 / 2 = 0.0615 moles O2 needed we have 0.0688 moles of O2 so O2 is in excess and Mg is the limiting reactant we get 0.123 moles of MgO => 0.123 mol x 40.31 g/mol =4.96 g
To find how many grams of silver nitrate can be produced, first determine the limiting reactant. Calculate the moles of silver nitrate and calcium chloride in the given volumes and concentrations. The reactant that produces fewer moles of silver nitrate will be the limiting reactant. Then use stoichiometry to find the amount of silver nitrate that can be produced from the limiting reactant.
The products of the reaction between magnesium (Mg) and hydrochloric acid (HCl) are magnesium chloride (MgCl2) and hydrogen gas (H2).
The molecular equation for the reaction between magnesium (Mg) and hydrochloric acid (HCl) is: Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g)
To determine the theoretical yield of magnesium chloride (MgCl₂) from the reaction of magnesium hydroxide (Mg(OH)₂) with hydrochloric acid (HCl), we first identify the balanced chemical equation: Mg(OH)₂ + 2 HCl → MgCl₂ + 2 H₂O. The molar mass of Mg(OH)₂ is approximately 58.3197 g/mol, and that of MgCl₂ is about 95.211 g/mol. Calculating the moles of Mg(OH)₂ in 50.6 g gives about 0.868 moles, while 45.0 g of HCl corresponds to about 1.23 moles. Since the reaction requires 2 moles of HCl for every mole of Mg(OH)₂, HCl is in excess. The limiting reagent is Mg(OH)₂, producing 0.868 moles of MgCl₂. Therefore, the theoretical yield of MgCl₂ is approximately 82.7 grams (0.868 moles × 95.211 g/mol).
The reaction is balanced, so the mole ratio of Mg to HCl is 1:2. Calculate the molar mass of HCl (1 mol HCl = 1g + 1g = 36.5g), then use stoichiometry to convert the mass of Mg to moles of HCl. Finally, divide the mass of Mg by 1 (from the ratio 1:2) and multiply by the molar mass of HCl to find the mass needed.
Mg + 2HCl = MgCl2 + H2 SO magnesium chloride and Hydrogen gas
The balanced equation for the reaction is: Mg(s) + 2HCl(aq) -> MgCl2(aq) + H2(g). To calculate the mass of HCl consumed, you need to know the molar mass of HCl (approximately 36.46 g/mol) and the molar ratio between HCl and Mg in the balanced equation (2 moles of HCl per 1 mole of Mg). Once you have the moles of Mg given, you can use the mole ratio to calculate the moles of HCl consumed, and then convert that to mass using the molar mass of HCl.
When hydrochloric acid (HCl) is mixed with magnesium (Mg), a chemical reaction occurs where hydrogen gas (H2) is produced and magnesium chloride (MgCl2) is formed. This reaction is represented by the following equation: 2HCl + Mg → MgCl2 + H2.