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744 g/L of ammonium sulphate, at 20 0C

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What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?

Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.


How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?

To make a 0.25 M solution of ammonium sulfate from a stock solution of 6 M, you would need to dilute the stock solution. The dilution equation is C1V1 = C2V2 where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution. You would need to set up this equation to calculate the volume of the stock solution needed and then convert that volume to grams using the molar mass of ammonium sulfate.


How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?

To make a 0.25M solution of ammonium sulfate at a concentration of 6M, you would need to dilute the 6M solution. Assuming you have 1 liter of the 6M solution, you can calculate the volume needed for dilution using the formula: (C1V1 = C2V2), where C1 = 6M, V1 = volume of the 6M solution (in liters), C2 = 0.25M, and V2 = total volume of the diluted solution (in liters). Once you have the volume, you can convert it to grams using the molar mass of ammonium sulfate.


What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?

The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.


Mass of 1.60 mol of ammonium sulfate?

you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g

Related Questions

What is the concentration of a saturated solution of copper sulfate?

The concentration of a saturated solution of copper sulfate is approximately 25% by weight, which means that 25 grams of copper sulfate are dissolved in 100 grams of water at a specific temperature. At room temperature, this solution is around 47-50 grams of copper sulfate per 100 milliliters of water.


Saturated copper sulfate solution contains 20 grams of CuSO4 per 100 grams of water What is the ww of CuSO4?

The weight/weight of CuSO4 in the saturated solution is 20%. This means that for every 100 grams of the solution, 20 grams are CuSO4.


How much copper sulfate would be needed to make a saturated solution of copper sulfate with 400g of water at 20 degree celsius?

To prepare a saturated solution of copper sulfate at 20 degrees Celsius, you would need to dissolve approximately 203 grams of copper sulfate in 400 grams of water. This is based on the solubility of copper sulfate in water at that temperature.


What mass of nitrogen in grams is present in 148 grams of ammonium sulfate?

Ammonium sulfate contains 21% nitrogen by mass. To find the mass of nitrogen in 148 grams of ammonium sulfate, you would first calculate 21% of 148 grams, which equals 31.08 grams of nitrogen.


What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?

The molar mass of ammonium sulfate is 132,14 g.


How many grams of ammonium sulfate are needed to make a .25 M solution at a concentration of 6M?

To make a 0.25 M solution of ammonium sulfate from a stock solution of 6 M, you would need to dilute the stock solution. The dilution equation is C1V1 = C2V2 where C1 and V1 are the concentration and volume of the stock solution, and C2 and V2 are the concentration and volume of the final solution. You would need to set up this equation to calculate the volume of the stock solution needed and then convert that volume to grams using the molar mass of ammonium sulfate.


How many grams of ammonium sulfate are needed to make a 0.25M solution at a concentration of 6M?

To make a 0.25M solution of ammonium sulfate at a concentration of 6M, you would need to dilute the 6M solution. Assuming you have 1 liter of the 6M solution, you can calculate the volume needed for dilution using the formula: (C1V1 = C2V2), where C1 = 6M, V1 = volume of the 6M solution (in liters), C2 = 0.25M, and V2 = total volume of the diluted solution (in liters). Once you have the volume, you can convert it to grams using the molar mass of ammonium sulfate.


What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?

The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.


What is the weight in grams of 1 mole of ammonium sulfate?

(NH4)2SO4 two nitrogen = 28.02 grams eight hydrogen = 8.064 grams one sulfur = 32.07 grams four oxygen = 64 grams =========================add = 132.154 grams per mole ----------------------------------


How much cerium sulfate is needed to make a saturated solution in 100 ml of water at 30 degrees celsius?

The solubility of cerium sulfate in water at 30 degrees Celsius is 114 g/L. To make a saturated solution in 100 ml of water, you would need to calculate the amount of cerium sulfate that can dissolve in that volume at that temperature. This would be approximately 11.4 grams of cerium sulfate.


Mass of 1.60 mol of ammonium sulfate?

you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g


How many grams of ammonium chloride are contained in 0.500L of a 2.00M solution?

To find the number of grams of ammonium chloride in 0.500L of a 2.00M solution, we need to use the formula: concentration (M) = moles of solute / volume of solution (L). First, calculate the moles of ammonium chloride present in 0.500L of the solution using C = n/V. Then, convert moles to grams by multiplying by the molar mass of ammonium chloride (NH4Cl).