1.5 moles
5.50
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
Ammonium chlorate is an inorganic compound with the formula NH4ClO3. ---- It is obtained by neutralizing chloric acid with either ammonia or ammonium carbonate, or by precipitating barium, strontium or calcium chlorates with ammonium carbonate or ammonium sulfate, producing the respective carbonate or sulfate precipitate and an ammonium chlorate solution. Ammonium chlorate crystallizes in small needles, readily soluble in water. On heating, ammonium chlorate decomposes at about 102 °C, with liberation of nitrogen, chlorine and oxygen. It is soluble in dilute aqueous alcohol, but insoluble in strong alcohol. This compound is a strong oxidizer and should never be stored with flammable materials. Ammonium chlorate is a very unstable oxidizer and will decompose, sometimes violently, at room temperature. It will explode when exposed to sunlight for a few minutes. Even solutions are known to be unstable. Because of the dangerous nature of this salt it should only be kept in solution when needed, and never be allowed to crystallize.
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The purpose of the ammonium acetate in the gravimetric determination of aluminium as oxinate is as a buffer. As more ammonium acetate is added, this caused the complex of the aluminium in the solution to precipitate after the yellow supernatant was formed. Excess ammonium acetate is needed to ensure all of the crystals precipitated out completely.
5.50
0.125 Molar solution! Molarity = moles of solute/Liters of solution Algebraically manipulated, Moles of copper sulfate = 2.50 Liters * 0.125 M = 0.313 moles copper sulfate needed ===========================
(NH4)+ is Ammonium ion and (CLO3)- is chlorate ion; therefore, the name of the substance would be: Ammonium Chlorate. It is an inorganic compound. It crystallizes in small needles, readily soluble in water. It decomposes at about 102 °C, with liberation of nitrogen, chlorine and oxygen. It is soluble in dilute aqueous alcohol, but insoluble in strong alcohol. Ammonium Chlorate is obtained by neutralizing chloric acid with either ammonia or ammonium carbonate, or by precipitating barium, strontium or calcium chlorates with ammonium carbonate or ammonium sulfate, producing the respective carbonate or sulfate precipitate and an ammonium chlorate solution. Ammonium chlorate is a strong oxidizer and should never be stored with flammable materials. It is very unstable, and will decompose, sometimes violently, at room temperature. This results from the mixture of the reducing ammonium cation and the oxidizing chlorate anion. Even solutions are known to be unstable. Because of the dangerous nature of this salt it should only be kept in solution when needed, and never be allowed to crystallize.
Ammonium chlorate is an inorganic compound with the formula NH4ClO3. ---- It is obtained by neutralizing chloric acid with either ammonia or ammonium carbonate, or by precipitating barium, strontium or calcium chlorates with ammonium carbonate or ammonium sulfate, producing the respective carbonate or sulfate precipitate and an ammonium chlorate solution. Ammonium chlorate crystallizes in small needles, readily soluble in water. On heating, ammonium chlorate decomposes at about 102 °C, with liberation of nitrogen, chlorine and oxygen. It is soluble in dilute aqueous alcohol, but insoluble in strong alcohol. This compound is a strong oxidizer and should never be stored with flammable materials. Ammonium chlorate is a very unstable oxidizer and will decompose, sometimes violently, at room temperature. It will explode when exposed to sunlight for a few minutes. Even solutions are known to be unstable. Because of the dangerous nature of this salt it should only be kept in solution when needed, and never be allowed to crystallize.
124,9 g grams of ammonium carbonate are needed.
Amount of sodium sulfate required = 0.683 x 350/100 = 0.239The formula mass of sodium sulfate, Na2SO4 is 2(23.0) + 32.1 + 4(16.0) = 142.1 Therefore mass of sodium sulfate required = 0.239 x 142.1 = 34.0g Approximately 34 grams of sodium sulfate would be needed.
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it is solubility
You need min. 5,63 g cerium sulfate.
164,7 mL are needed.
Depending on the desired concentration of the solution !
The answer is 1 471,5 mL.