This mass is 59,463 g.
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
The calculated value might be -281.86 kcal/mol or 1179.3 J/mol. See Ref: J. Chem. Educ., 1965, 42 (9), 474
To find the mass of sodium sulfate, we need to know the molar mass of Na2SO4, which is about 142.04 g/mol. Multiply the number of moles by the molar mass to get the mass: 0.150 mol * 142.04 g/mol = 21.31 grams. So, the mass of 0.150 mol of sodium sulfate is 21.31 grams.
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
The molar mass of ammonium sulfate is 132,14 g.
Ammonium sulfate has the chemical formula (NH4)2SO4. The molar mass of nitrogen is 14.01 g/mol and the molar mass of (NH4)2SO4 is 132.14 g/mol. Therefore, the percentage by mass of nitrogen in ammonium sulfate is (2*14.01)/(132.14) * 100% = 21.2%.
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
The molar mass of NH42 SO4 = 152.40278 g/mol
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
To determine the mass of ammonium sulfate needed to make a 0.5 M solution: Calculate the molar mass of ammonium sulfate (NH4)2SO4. Use the formula: Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol). Plug in the values: Molarity = 0.5 M, Volume = 0.5 L, and Molar mass of (NH4)2SO4. Calculate to find the mass of ammonium sulfate required.
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
14% FeThe formula for iron ammonium sulfate hexahydrate is (NH4)2Fe(SO4)2·6H2O, which can also be written as FeH20N2O14S2.To determine the percentage of Fe in the compound, divide the mass of Fe by the mass of the compound and multiply by 100. The molar mass of Fe is 56 g/mol. The molar mass of the compound is 392 g/mol. There is only one Fe atom in the formula, so the mass of Fe is 56 g/mol.%Fe = (56 g/mol)/(392 g/mol) x 100 = 14%
The equivalent weight of ferric ammonium sulfate is 392.14 g/mol.
The formula mass of ammonium carbonate (NH4)2CO3 is 96.09 g/mol. Since the formula contains two ammonium ions, the molar mass of ammonium carbonate is 96.09 g/mol * 2 = 192.18 g/mol.
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.