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Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
What is the molar mass of ammonium nitrate?
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
What is the standard heat of formation of ammonium sulfate?
The calculated value might be -281.86 kcal/mol or 1179.3 J/mol. See Ref: J. Chem. Educ., 1965, 42 (9), 474
What is the mass in grams of 0.150 mol of sodium sulfate?
To find the mass of sodium sulfate, we need to know the molar mass of Na2SO4, which is about 142.04 g/mol. Multiply the number of moles by the molar mass to get the mass: 0.150 mol * 142.04 g/mol = 21.31 grams. So, the mass of 0.150 mol of sodium sulfate is 21.31 grams.
Mass of 1.60 mol of ammonium sulfate?
you take the molar mass of ammonium sulfate (132.144) and multiply that by the 1.60 moles you are already given to get the answer, 211.4034 grams the equation looks like this: 132.144*1.60=211.4304 g
What is the weight in grams of 1 mole of ammonium sulfate (NH4)2SO4?
The molar mass of ammonium sulfate is 132,14 g.
What is the percentage by mass of nitrogen in ammonium sulphate?
Ammonium sulfate has the chemical formula (NH4)2SO4. The molar mass of nitrogen is 14.01 g/mol and the molar mass of (NH4)2SO4 is 132.14 g/mol. Therefore, the percentage by mass of nitrogen in ammonium sulfate is (2*14.01)/(132.14) * 100% = 21.2%.
What is the weight in grams of 1 mole of ammonium sulfate NH42 SO4?
The molar mass of ammonium sulfate, (NH4)2SO4, is 132.14 g/mol. Therefore, 1 mole of ammonium sulfate weighs 132.14 grams.
What is the molar mass of nh42 so4?
The molar mass of NH42 SO4 = 152.40278 g/mol
How many moles of ammonium sulfate are in 150g sample?
To find the number of moles of ammonium sulfate in a 150g sample, you first need to calculate the molar mass of ammonium sulfate (NH4)2SO4, which is approximately 132.14 g/mol. Then, divide the given mass (150g) by the molar mass to get the number of moles, which would be approximately 1.14 moles.
What mass of ammonium sulphate is required to produce 0.5 liters of mole solution?
To determine the mass of ammonium sulfate needed to make a 0.5 M solution: Calculate the molar mass of ammonium sulfate (NH4)2SO4. Use the formula: Mass (g) = Molarity (M) x Volume (L) x Molar mass (g/mol). Plug in the values: Molarity = 0.5 M, Volume = 0.5 L, and Molar mass of (NH4)2SO4. Calculate to find the mass of ammonium sulfate required.
What is the mass in grams of 1.15 mol of strontium sulfate?
To find the mass of 1.15 mol of strontium sulfate, you first need to calculate the molar mass of strontium sulfate, which is 183.68 g/mol. Then, multiply the molar mass by the number of moles: 1.15 mol * 183.68 g/mol = 211.22 grams. Therefore, the mass of 1.15 mol of strontium sulfate is 211.22 grams.
What is the percentage of Fe in iron ammonium sulfate hexahydrate?
14% FeThe formula for iron ammonium sulfate hexahydrate is (NH4)2Fe(SO4)2·6H2O, which can also be written as FeH20N2O14S2.To determine the percentage of Fe in the compound, divide the mass of Fe by the mass of the compound and multiply by 100. The molar mass of Fe is 56 g/mol. The molar mass of the compound is 392 g/mol. There is only one Fe atom in the formula, so the mass of Fe is 56 g/mol.%Fe = (56 g/mol)/(392 g/mol) x 100 = 14%
What is the equivalent weight of ferric ammonium sulphate?
The equivalent weight of ferric ammonium sulfate is 392.14 g/mol.
Determine both the formula mass and molar mass of ammonium carbonate?
The formula mass of ammonium carbonate (NH4)2CO3 is 96.09 g/mol. Since the formula contains two ammonium ions, the molar mass of ammonium carbonate is 96.09 g/mol * 2 = 192.18 g/mol.
What is the molar mass of ammonium nitrate?
The molar mass of ammonium nitrate (NH4NO3) is approximately 80.04 g/mol.
