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14% Fe

The formula for iron ammonium sulfate hexahydrate is (NH4)2Fe(SO4)2·6H2O, which can also be written as FeH20N2O14S2.

To determine the percentage of Fe in the compound, divide the mass of Fe by the mass of the compound and multiply by 100. The molar mass of Fe is 56 g/mol. The molar mass of the compound is 392 g/mol. There is only one Fe atom in the formula, so the mass of Fe is 56 g/mol.

%Fe = (56 g/mol)/(392 g/mol) x 100 = 14%

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Related Questions

How many water molecules are bound to iron II ammonium sulfate?

Six water molecules are bound to iron (II) ammonium sulfate.


What is the balanced equation for Ammonium sulfate and iron sulphate?

no reaction between ammonium sulphate and iron sulphate


Is ferric ammonium sulfate a metal?

No, it contains metals in its formula, but is not a metal itself.


How do you salt from an equation iron 3 hydroxide reacting with ammonium sulphate?

To determine the products formed from the reaction between iron(III) hydroxide and ammonium sulfate, first write out the balanced chemical equation. Then, identify the cation and anion in each compound. The cation from the reactants will combine with the anion from the other compound to form the salt. In this case, iron(III) hydroxide will react with ammonium sulfate to form iron(III) sulfate as the salt along with ammonium hydroxide.


Why mohr's salt is used instead of ferrous sulphate in redox titration?

Mohr's salt (ammonium iron(II) sulfate hexahydrate) is used instead of ferrous sulfate in redox titrations because it is more stable and less prone to oxidation by air compared to ferrous sulfate. This helps in achieving more accurate and reliable results in redox titrations.


How do you prepare ferrous ammonium sulphate?

To prepare ferrous ammonium sulfate, commonly known as Mohr's salt, dissolve iron(II) sulfate and ammonium sulfate in water separately. Combine the two solutions and allow the double displacement reaction to occur, resulting in the formation of ferrous ammonium sulfate. Finally, crystallize the solution to obtain the solid compound.


What are the formulas for barium fluoride sodium oxide iron sulfate and ammonium sulfate?

The formula for barium fluoride is BaF₂, for sodium oxide is Na₂O, for iron sulfate is FeSO₄, and for ammonium sulfate is (NH₄)₂SO₄. Each formula represents the composition of the respective compound, indicating the elements and their ratios.


What is percentage composition of ironII sulfate hexahydrate?

The percentage composition of iron(II) sulfate hexahydrate (FeSO₄·6H₂O) can be calculated by determining the molar mass of the compound and the mass contributions of each element. The molar mass is approximately 278.01 g/mol, with iron (Fe) contributing about 55.85 g/mol, sulfur (S) about 32.07 g/mol, oxygen (O) about 64.00 g/mol, and water (H₂O) contributing about 108.12 g/mol. The percentage of each component can then be calculated as follows: Fe (20.1%), S (11.5%), O (23.0%), and H₂O (38.9%).


What is the percentage by mass of 5grams of iron sulfate dissolved in 75grams of water?

The mass of the solution is 5g (iron sulfate) + 75g (water) = 80g. Therefore, the percentage by mass of iron sulfate in the solution is (5g / 80g) * 100% = 6.25%.


What is the balanced equation for Iron II sulfate and ammonium sulfide?

iron(II) sulfide + sulfuric acid --> hydrogen sulfide + iron(II) sulfate FeS + H2SO4 --> H2S + FeSO4


Examples of primary standards used in acidbase titrations?

Oxalic acid,sodium oxalate or ammonium iron (II) sulfate.


What complexes of iron are visible?

Iron complexes that are visible include iron(III) thiocyanate complex (blood red), iron(II) hexahydrate complex (light green), and iron(III) chloride hexahydrate complex (yellow-brown).