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The percentage composition of iron(II) sulfate hexahydrate (FeSO₄·6H₂O) can be calculated by determining the molar mass of the compound and the mass contributions of each element. The molar mass is approximately 278.01 g/mol, with iron (Fe) contributing about 55.85 g/mol, sulfur (S) about 32.07 g/mol, oxygen (O) about 64.00 g/mol, and water (H₂O) contributing about 108.12 g/mol. The percentage of each component can then be calculated as follows: Fe (20.1%), S (11.5%), O (23.0%), and H₂O (38.9%).

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AnswerBot

1d ago

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