0,25 moles F2
Whatever be the substance the one gram mole of that substance would have 6.023 x 1023 atoms or molecules or ions in it. Hence to get the mole just divide the number given by 6.023 x 1023
This is equivalent to 1,4 moles.
To find the number of moles in 1.01e23 fluorine atoms, divide the given number of atoms by Avogadro's number, which is approximately 6.022e23. So, 1.01e23 F atoms / 6.022e23 atoms/mol ≈ 0.168 moles of F atoms.
5,82 x 1023 atoms of tungsten equal 0,966 moles.
9,003 x 1023 atoms of iron correspond to 1,495 moles.
56 moles × (6.02 × 1023) = 3.37 × 1024 atoms
1.50 x 10 to the 23 atoms of fluorine is equal to 0,249 moles.
Atomic Mass of Na: 23.0 grams1.50 moles × (6.02 × 1023 atoms) = 9.03 × 1023atoms
There are 1.93 moles in 1.16 x 10^23 fluorine atoms. This calculation is done by dividing the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol).
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
There are 19.2 moles of fluorine in 3.2 moles of xenon hexafluoride. Xenon hexafluoride has 6 fluorine atoms in each molecule, so you multiply the moles of xenon hexafluoride by 6 to find the moles of fluorine.
5.66 x 10^23 atoms of xenon is equal to 0.094 moles.