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What is the mass in grams of 3.011 1023 atoms F?
To find the mass of 3.011 × 10²³ atoms of fluorine (F), first note that the molar mass of fluorine is approximately 19.00 g/mol. Since 1 mole contains Avogadro's number (approximately 6.022 × 10²³) of atoms, the number of moles in 3.011 × 10²³ atoms is 3.011 × 10²³ / 6.022 × 10²³ ≈ 0.5 moles. Therefore, the mass is 0.5 moles × 19.00 g/mol = 9.50 grams.
How many atoms of F are in 5.88 mg of ClF3?
To find the number of fluorine (F) atoms in 5.88 mg of ClF3, first calculate the molar mass of ClF3. ClF3 has a molar mass of 83.45 g/mol. Convert 5.88 mg to grams (0.00588 g) and then use the molar mass to find the number of moles of ClF3. Since there are 3 F atoms in each molecule of ClF3, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 3 to find the number of F atoms. In this case, there are approximately 4.24 x 10^20 F atoms in 5.88 mg of ClF3.
How many moles of fluorine in 3 moles of borontrifluoride?
Boron trifluoride is BF3. So each mole of BF3 contains 1 moles of boron (B) and 3 moles of fluorine (F). Thus, 3 moles of BF3 contains NINE moles of fluorine.
How many moles are in 45g of F?
The molecular mass of fluorine gas, F2 is 2(19.0) = 38.0Amount of F2 = mass of sample/molar mass = 9.5/38.0 = 0.25mol There are 0.25 moles of fluorine in a 9.5g pure sample.
How many atoms are in 2NaF?
To determine the number of atoms in 2NaF, we first need to break down the formula. "2Na" indicates 2 atoms of sodium, while "F" represents 1 atom of fluorine. Therefore, 2NaF contains a total of 3 atoms: 2 atoms of sodium and 1 atom of fluorine.
How many moles are in 1.16 1023 F atoms?
There are 1.93 moles in 1.16 x 10^23 fluorine atoms. This calculation is done by dividing the number of atoms by Avogadro's number (6.022 x 10^23 atoms/mol).
What is the mass of 4 moles of fluorine atoms?
The mass of 4 moles of fluorine F atoms is 151,98 g (because fluorine is a diatomic element).
What is the amount in moles of 1.50 x 1023 atoms F?
Amount of F atoms = (1.50x1023)/(6.02x1023) = 0.249mol Note: F in elemental form exists as diatomic F2 so the amount of fluorine gas would be 0.125mol.
What is the mass in grams for 3.011 X 10 23 atoms F?
1 mole of any element is its atomic weight (from the periodic table) in grams.1 mole of atoms of an element is 6.022 x 1023 atoms (Avogadro's number).1 mole F = 18.9984032g F1 mole F = 6.022 x 1023 atoms FConvert atoms of F to moles F.3.011 x 1023 atoms F x (1mole F/6.022 x 1023 atoms F) = 0.5000 mole FConvert moles F to g F.0.5000 mole F x (18.9984032g F/1mole F) = 9.499g Fe
How many F atoms in 19g of CH2F2?
One mole of CH2F2 has a mass of (12.011)+2(1.0079)+2(18.9984) g = 52.0236 g 19 g of CH2F2 is equivalent to 19/52.0236 moles = 0.3652 moles For every mole of CH2F2 there are 2 F atoms, and 1 mole of a substance has 6.022 x 10^23 entities. So 19 g of CH2F2 has 2(0.3652)(6.022 x 10^23) F atoms = 4.40 x 10^23 F atoms.
How many atoms are present in 4.0 moles?
To determine the number of atoms present in 4.0 moles, you can use Avogadro's constant, which is 6.022 x 10^23 atoms/mol. Therefore, in 4.0 moles, there would be 4.0 x 6.022 x 10^23 atoms, which equals 2.409 x 10^24 atoms. This calculation is based on the concept that one mole of any substance contains Avogadro's number of atoms or molecules.
What is the mass in grams of 3.011 1023 atoms F?
To find the mass of 3.011 × 10²³ atoms of fluorine (F), first note that the molar mass of fluorine is approximately 19.00 g/mol. Since 1 mole contains Avogadro's number (approximately 6.022 × 10²³) of atoms, the number of moles in 3.011 × 10²³ atoms is 3.011 × 10²³ / 6.022 × 10²³ ≈ 0.5 moles. Therefore, the mass is 0.5 moles × 19.00 g/mol = 9.50 grams.
How many moles of molecules are there in 38g of fluorine F2?
To calculate the number of moles of F2 molecules in 38g, we first need to determine the molar mass of F2, which is 38 grams/mol. Next, we can use the formula: moles = mass / molar mass. Therefore, the number of moles in 38g of F2 is 1 mole.
How many atoms of F are in 5.88 mg of ClF3?
To find the number of fluorine (F) atoms in 5.88 mg of ClF3, first calculate the molar mass of ClF3. ClF3 has a molar mass of 83.45 g/mol. Convert 5.88 mg to grams (0.00588 g) and then use the molar mass to find the number of moles of ClF3. Since there are 3 F atoms in each molecule of ClF3, multiply the number of moles by Avogadro's number (6.022 x 10^23) and then by 3 to find the number of F atoms. In this case, there are approximately 4.24 x 10^20 F atoms in 5.88 mg of ClF3.
How many moles of H2SO4 are needed to react with 2.4 moles of Aluminum metal?
0.8 moles Explanation: from the equation we can see, 2 mole A l is needed to react completely with 3 mole F e O so, 3 moles of F e O needs 2 moles A l so, 1 mole F e O needs 2 3 moles A l so, 1.2 mol F e O needs 2 × 1.2 3 moles A l = 0.8 moles A l
How many atoms of fluorine are there in 2.5 mol?
1 mole F = 6.022 x 1023 atoms F 2.5mol F x 6.022 x 1023 atoms F/1mol F = 1.5 x 1024 atoms F
How many moles in 76 grams of fluorine?
To find the number of moles in 76 grams of fluorine, you first need to determine the molar mass of fluorine, which is approximately 19 grams per mole. Then, you divide the given mass (76 grams) by the molar mass of fluorine to get the number of moles. In this case, 76 grams of fluorine is equal to approximately 4 moles.
