1 mole F = 6.022 x 1023 atoms F
2.5mol F x 6.022 x 1023 atoms F/1mol F = 1.5 x 1024 atoms F
(NH4)2Sthere are 8 hydrogen atoms for every molecule ofammoniumsulfideNA = 4 mol x 6.02 x 10^23 = 2.4 x 10^24 molecules of ammonium sulfidenumber of hydrogen atoms = 8 x2.4 x 10^24 = 2.93 x 10^25 ( 3 sig. figure)
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
It is 25 moles of Sodium Hydroxide (;
76.2 mol Ag
The density of copper (Cu) is about 8.92 g/cm3. So 1 cm3 of copper is about 8.92 g. Next find the number of moles in 8.92 g of copper by dividing by its molecular weight:8.92 g Cu / 63.54 g/mol Cu = 0.14038 mol CuBy definition 1 mol of any substance is Avogadro's number of atoms or, 6.022 x 10 23 atoms.So, 0.14038 mol Cu * [6.022x1023 atoms Cu / mol Cu] = 8.45x1022 atoms of Cu
Approx 7.925*10^23 atoms.
360 g H2O x 1 mol/18g H2O x 6.02x10^23 H2O molecules/mol x 2 H atoms/molecule = 2.4x10^25 hydrogen atoms.
5.0x10^25 * (1 mol / 6.022x10^23 atoms) = 83 moles of iron.
8.70 moles (NH4)2S x 6.02x10^23 molecules/mole x 8 H atoms/molecule = 4.18x10^25 H atoms
I assume you mean 4.6 X 10^25 atoms. This is the conversion. 4.6 X 10^25 atoms Cu ( 1mol Cu/ 6.022 X 10^23 )( 63.55 grams Cu/ 1 mol Cu ) = 4854.37 grams Cu
593 g H2O x 1 mol/18 g x 2 mole H/mole H2O x6.02x10^23 H atoms/mole H = 4x10^25 atoms of H
17
(NH4)2Sthere are 8 hydrogen atoms for every molecule ofammoniumsulfideNA = 4 mol x 6.02 x 10^23 = 2.4 x 10^24 molecules of ammonium sulfidenumber of hydrogen atoms = 8 x2.4 x 10^24 = 2.93 x 10^25 ( 3 sig. figure)
16 g O x 1 mol/16 g = 1 mole and 1 mole = 6.02x10^23 atoms of O8g S x 1 mol/32 g = 0..25 moles S and then 0..25 moles x 6.02x10^23 atoms/mole = 1.5x10^23 atoms of S, or rounding to 1 significant figure, you have 2x10^23 atoms of S
25 mmol equates to 0.025 mol
2 moles C8H18 (18 moles H/1 mole C8H18)(6.022 X 10^23/1 mole H) = 2.2 X 10^25 atoms of hydrogen
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g