Since the formula unit of copper is a single atom, the answer is 85 X Avogadro's Number or about 5.119 X 1025.
A chemical formula that contains 6 copper (Cu) atoms is Cu₆. This formula indicates that there are six individual copper atoms present in the compound. Copper can also form various compounds, but in its elemental form, it can simply be represented as Cu₆.
Copper(II) nitrate has six oxygen atoms.
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
Divide that number of atoms by 6.02x10^23 atoms/mole
One mole is 2.06x10 to the 23 atoms. Therefore if there is 1.48x10 to the 25 cu atoms, we would have to divide the two values to obtain the moles of the present cu atoms. So 1.48x10 to the 25 divided by 2.06x10 to the 23 would result in 24.6 moles of cu.
A chemical formula that contains 6 copper (Cu) atoms is Cu₆. This formula indicates that there are six individual copper atoms present in the compound. Copper can also form various compounds, but in its elemental form, it can simply be represented as Cu₆.
Copper(II) nitrate has six oxygen atoms.
There are 5 atoms in one molecule of Cu(OH)2, comprising one copper (Cu) atom, two oxygen (O) atoms, and two hydrogen (H) atoms.
Cu(NO3)2 has 9 atoms 1 Cu atom 2 N atoms 6 O atoms
14.0 g x 1 mole/187.56 g = 0.0746 moles0.0746 moles Cu(NO3)2 x 6 moles O/mole Cu(NO3)2 = 0.448 moles O atoms0.448 moles O atoms x 6.02x10^23 atoms/mole = 2.70x10^23 atoms of oxygen
The compound copper nitrate has Cu(NO3)2 for a chemical formula. In that formula, we see that there is an NO3 radical present, and that there are 3 atoms of oxygen in that radical (the sub 3 after the O). But there are 2 of those NO3 radicals (the sub 2 outside of the parens) present in this compound. That means that there are 3 x 2 oxygen atoms in a molecule of copper nitrate, or 6 atoms of oxygen in Cu(NO3)2.
4.0 moles Cu (6.022 X 1023/1 mole Cu) = 2.4 X 1024 atoms of copper ====================
Divide that number of atoms by 6.02x10^23 atoms/mole
One mole is 2.06x10 to the 23 atoms. Therefore if there is 1.48x10 to the 25 cu atoms, we would have to divide the two values to obtain the moles of the present cu atoms. So 1.48x10 to the 25 divided by 2.06x10 to the 23 would result in 24.6 moles of cu.
1 mol Cu Atoms (6.02x10^23 atoms)
There are 11 atoms in one formula unit of Cu(NO3)2: one copper atom (Cu), two nitrogen atoms (N), six oxygen atoms (O), and two nitrogen atoms (N) from the nitrate (NO3) group.
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