.071 moles
800 g oxygen are needed.
5 moles of lead is equal to 1 036 g.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
Using the stoichiometry of the reaction, the molar ratio of C8H18 to CO2 is 2:16. Therefore, if 4.000 moles of C8H18 are consumed, 16/2 * 4.000 moles of CO2 will be produced. This results in 32.000 moles of CO2, which can be converted to grams using the molar mass of CO2 to get the theoretical yield in grams.
25,000 grams
Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
To calculate the number of moles in 25 grams of NaCl, divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Therefore, 25 grams of NaCl is equivalent to approximately 0.43 moles.
800 g oxygen are needed.
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
5 moles of lead is equal to 1 036 g.
25 moles of sulfur dioxide contain 600 grams of oxygen. Each mole of SO2 contains 2 moles of oxygen, and the molar mass of O is 16 g/mol. So, 25 moles x 2 moles = 50 moles of O, which is 50 moles x 16 g/mol = 800 g of O.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
There are approximately 3.01 moles of urea in 25 g of CONH2, so there are 3.01 moles of nitrogen atoms. Therefore, there are 3.01 moles * 2 nitrogen atoms/molecule = 6.02 moles of nitrogen atoms in 25 g of CONH2, or urea.
For this you need the atomic (molecular) mass of H2O. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. H2O= 18.0 grams2.5 moles H2O × (18.0 grams) = 45.0 grams H2O
0.25 grams for 25 centigrams.
Using the stoichiometry of the reaction, the molar ratio of C8H18 to CO2 is 2:16. Therefore, if 4.000 moles of C8H18 are consumed, 16/2 * 4.000 moles of CO2 will be produced. This results in 32.000 moles of CO2, which can be converted to grams using the molar mass of CO2 to get the theoretical yield in grams.
how many cals in 25 grams of sugar