25 moles of sulfur dioxidecontain 800,825 g oxygen.
25,1 grams sulfur contain 4,7147765.10e23 atoms.
22 grams carbon dioxide (0.5 moles)
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
If all of the quantities stated actually reacted, the law of the conservation of mass shows that the mass of carbon dioxide produced would be 40 - 18 or 22 grams.
3.82g of SO2 equals 0,06 moles.
800 g oxygen are needed.
Sulfur has relative atomic mass of 32 and oxygen have that of 16. The molar mass of sulfur dioxide is 64 grams per mole. Therefore there is approximately 0.58 moles (37.14/64) of sulfur dioxide in given weight.
25,1 grams sulfur contain 4,7147765.10e23 atoms.
22 grams carbon dioxide (0.5 moles)
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
72 grams SO2 (1 mole SO2/64.07 grams)(6.022 X 1023/1 mole SO2) = 6.8 X 1023 molecules of sulfur dioxide ============================
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.
We need 14,8 g oxygen.
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
The mass is 11 g.
54,9 mmol of sulfur dioxide is equivalent to 3,517 g.