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What is 2.50 mol of sulfur?

Updated: 4/28/2022
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1 mol Sulfur is 32 g Sulfur

So 2.5 mol Sulfur is 80 g Sulfur

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Q: What is 2.50 mol of sulfur?
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0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.


How many sulfur atoms are there in 0.250 mol of sulfur?

1.51 x 1023


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+694kJ/mol


What is the mass of 1.6 mol of the element?

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How do the rates of diffusion of oxygen and sulfur dioxide compare Molar masses Oxygen is 32 g mol and sulfur dioxide is 64 g mol?

Oxygen diffuses 1.4 times as fast as sulfur dioxide.


How do the rates of diffusion of helium and sulfur dioxide compare Molar masses Helium is 4 g mol and sulfur dioxide is 64 g mol?

Helium diffusses 4 times as fast as sulfur dioxide.


How many sulfur dioxide molecules are there in 1.80 mol of sulfur dioxide?

10.84 to the 23 power


How do you find 2.5 mol of sulfur in grams?

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What is the relative atomic mass for sulfur?

256.52 g mol-1since sulfur molecules are S8.


What is the mass in grams of 0.75 mol of sulfur which has a molar mass of approximately 32g mol?

= 0.75 mol x 32 g.mol-1 = 24 g


What is the percent composition of each element found in ammonium sulfide?

The formula unit for ammonium sulfide is (NH3)2S. There are 2 nitrogen atoms, 6 hydrogen atoms, and 1 sulfur atom per formula unit. Its molar mass is 66.12g/mol. Mass of Nitrogen = 14.007g/mol x 2 = 28.014g/mol Percent Composition of Nitrogen = (28.014g/mol)/(66.12g/mol) x 100 = 42.37% Mass of Hydrogen = 1.008g/mol x 6 = 6.048g/mol Percent Composition of Hydrogen = (6.048g/mol)/(66.12g/mol) x 100 = 9.147% Mass of Sulfur = 32.06g/mol Percent Composition of Sulfur = (32.06g/mol)/(66.12g/mol) x 100 = 48.49% 42.37% + 9.147% + 48.49% = 100.00%


molality How many sulfur atoms are in 1.56g sulfur When atomic mass of sulfur is 32.06g/mol?

To find the number of sulfur atoms in a given mass of sulfur, you can use the following steps: Determine the number of moles of sulfur using the formula: moles = mass molar mass moles= molar mass mass ​ Given that the molar mass of sulfur ( S S) is 32.06 g/mol and the mass ( m m) is 1.56 g: moles = 1.56   g 32.06   g/mol moles= 32.06g/mol 1.56g ​ Once you have the moles of sulfur, you can use Avogadro's number (6.022 x 1 0 23 10 23 mol − 1 −1 ) to find the number of atoms: number of atoms = moles × Avogadro’s number number of atoms=moles×Avogadro’s number Let's calculate it: moles = 1.56   g 32.06   g/mol ≈ 0.0488   mol moles= 32.06g/mol 1.56g ​ ≈0.0488mol number of atoms = 0.0488   mol × ( 6.022 × 1 0 23   mol − 1 ) number of atoms=0.0488mol×(6.022×10 23 mol −1 ) number of atoms ≈ 0.0488 × 6.022 × 1 0 23 number of atoms≈0.0488×6.022×10 23 number of atoms ≈ 3.0 × 1 0 22 number of atoms≈3.0×10 22 Therefore, there are approximately 3.0 × 1 0 22 3.0×10 22 sulfur atoms in 1.56 g of sulfur.