Sr is 87.6g/mol, and 25/87.6 = 0.285 moles.
17.24 g Sr * 1 mol/87.62 g Sr = 0.1968 mols Sr
To determine the number of atoms in 16.3 g of strontium (Sr), you first need to calculate the number of moles using the molar mass of Sr (87.62 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. The final calculation results in approximately 1.11 x 10^23 atoms of strontium in 16.3 g.
Yes, the equation is balanced. Two moles of Sr react with one mole of O2 to produce two moles of SrO.
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Well, honey, strontium chloride has a molar mass of about 158.53 grams per mole. So, if you're looking for the amount of grams in a specific quantity of strontium chloride, you'll need to do a little math based on the number of moles you have. But hey, don't stress too much, just grab a calculator and you'll have your answer in no time.
The balanced equation for the reaction between strontium and water is: 2 Sr + 2 H2O → 2 Sr(OH)2 + H2 This equation shows that two moles of strontium react with two moles of water to produce two moles of strontium hydroxide and one mole of hydrogen gas. The equation is balanced as the number of atoms of each element is the same on both sides of the reaction.
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25 million
Cal Ripken Sr. died on March 25, 1999 at the age of 63.
To determine the mass of strontium hydroxide (Sr(OH)₂) needed to neutralize a given volume of citric acid (C₆H₈O₇) with a specific molarity, you'll first need to calculate the moles of citric acid present in the solution. Since citric acid is a triprotic acid, each mole can react with three moles of hydroxide ions (OH⁻). Using the equation for the neutralization reaction, you can then find the required moles of Sr(OH)₂. Finally, convert the moles of Sr(OH)₂ to mass using its molar mass.
To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.