How many moles of calcium ca atoms are in 98.5 g of ca?

Answer 1

The Atomic Mass of calcium, Ca is 40.1. First we calculate the amount in moles of calcium in a 98.5g pure sample.Amount of Ca = 98.5/40.1 = 2.46mol

So there are 2.46 moles of Ca (or Ca atoms).

Answer 2

To determine the number of moles of calcium atoms in 98.5 g of Ca, you need to first calculate the molar mass of Ca (40.08 g/mol). Then, divide the given mass by the molar mass to get the number of moles. So, 98.5 g of Ca is equal to 98.5 g / 40.08 g/mol ≈ 2.46 moles of Ca atoms.

Answer 3

77.4 gCa x 1 Mole Ca/40.08 gCa = 1.931 mol Ca

Answer 4

801 g Ca * (1 mole Ca/40.08 g Ca) = 19.985 moles

There are about 20 moles of calcium atoms in 801 grams of calcium

Answer 5

0.688 grams Ca (1mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca)(1mol Ca/6.022 X 10^23)

= 0.0172 moles of calcium atoms in 0.688 grams of calcium.

Answer 6

84.7 grams Ca (1 mole Ca/40.08 grams)(6.022 X 10^23/1 mole Ca)

= 1.27 X 10^24 atoms of Calcium

Answer 7

6.022 x 10^23

40.1g Ca * 1 mole Ca/40.1g Ca * 6.02x10^23 atoms Ca/1 mole Ca = 6.02x10^23 atoms Ca.

-KG1

Answer 8

Calcium, Ca has atomic mass of 40.1

Amount of Ca = 77.4/40.1 = 1.93mol

There are 1.93 moles of calcium in a 77.4 gram sample.

Answer 9

The molar mass of Sr(OH)2 is

Answer 10

1.93 mol