1.51x10^24 atoms of O
3.15 x 6.02x1023 = 1.8963x1024 then multiply by two because there are 2 O atoms.1.8963x1024 x 2 = 3.7926x1024 O atoms
3.65 moles sucrose (11 mole O/1 mole C12H22O11)(6.022 X 1023/1 mole O) = 2.42 X 1025 atoms of oxygen ====================
12.54 (g O2) / 2*15.99 (g/mol O2) = 0.3921 mol O2 -->0.3921 (mol O2) * 6.022*1023 (molecules O2)/(molO2) == 2.361*1023 molecules O2= 4.723*1023 atoms O
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
1.51x10^24 atoms of O
3.15 x 6.02x1023 = 1.8963x1024 then multiply by two because there are 2 O atoms.1.8963x1024 x 2 = 3.7926x1024 O atoms
16.0 lbs = 7,257 g of O2 Oxygen exists in the gas form as 02 7,257g O2 * 1 mol O2/ 32 g * 2 mol O / 1 mol O2 * 6.022x10^23 atoms/mol = 2.73E26 atoms of O
The answer is 0,068 mol (for O not for O2).
3.30 gSiO2 / 60.085g SiO2 x 2 mol 0 / 1 mol SiO2 x (6.022*1023 )= 6.61*1022 O atoms
1mol O = 16.0g (rounded to 1 decimal place) 1mol O atoms = 6.022 x 1023 atoms 16g O x 1mol/16g = 1mol O 1mol O x 6.022 x 1023atoms/mol = 6.022 x 1023 atoms O
3.65 moles sucrose (11 mole O/1 mole C12H22O11)(6.022 X 1023/1 mole O) = 2.42 X 1025 atoms of oxygen ====================
12.54 (g O2) / 2*15.99 (g/mol O2) = 0.3921 mol O2 -->0.3921 (mol O2) * 6.022*1023 (molecules O2)/(molO2) == 2.361*1023 molecules O2= 4.723*1023 atoms O
1 mol Ba X (137.33 g Ba / mol Ba) = 137.33 g Ba2 mol O X (16.00 g O / mol O) = 32.00 g O2 mol H X (1.01 g H / mol H) = 2.02 g HMolar mass of Ba(OH)2 = 171.35 g/mol
first work out how many moles of Mg(OH)2 you have. n = m /M = 3.33 / 58 = 0.0574 mol Then from this work out how many mol of O you have. there are two oxygens in the formula so you have 0.0574 x 2 mol of O = 0.1148 mol 1 mol = 6.023x 1023 particles. So 6.023 x 10 23 /1 x 0.1148 = 6.92 x 10 22
Ans:Quartz is SiO2. It has a formula weight of 60.1 g/mol. 3 grams of SiO2 is 0.05 moles.Each mole of SiO2 has 0.1 moles of oxygen since there are 2 oxygen atoms per formula unit of SiO2.(1 mole of anything is 6.02x1023 of anything.)0.1 mol oxygen atoms x 6.02x1023 oxygen atoms / mol oxygen atoms= 6.02 x 1022 oxygen atoms.Number of O atoms =6.02×1022
16.0 g Fru = [16 (g) / 180 (g/mol Fru)] * [6 (mol O) / 1 (mol Fru)] * 16 (g O)/mol O) = 8.53 g O