In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
The number of atoms is seven.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
Cyanic acid contain four atoms.
In the chemical formula P2O5, there are 2 phosphorus (P) atoms and 5 oxygen (O) atoms. To find the total number of atoms, you simply add these numbers together: 2 + 5 = 7. Therefore, there are a total of 7 atoms in P2O5.
There are 1.15 x 10^21 atoms in 0.220 g of P2O5.
To find the total number of atoms in 0.850 g of P2O5, we need to first calculate the number of moles of P2O5 using its molar mass. Then, using Avogadro's number (6.022 x 10^23 atoms/mole), we can determine the total number of atoms. Finally, the answer is approximately 2.57 x 10^22 atoms in 0.850 g of P2O5.
To find the total number of atoms in 0.750 mol of P2O5, first calculate the molar mass of P2O5 (141.94 g/mol). Then multiply the molar mass by Avogadro's number (6.022 x 10^23 atoms/mol) to find the total number of atoms in 0.750 mol.
There are 200 atoms in 25 molecules of P2O5. Each molecule of P2O5 contains a total of 7 atoms (2 phosphorus atoms and 5 oxygen atoms). Multiplying this by 25 molecules gives a total of 175 atoms from oxygen and 50 atoms from phosphorus, adding up to 200 atoms in total.
The formula P2O5, could itself represent one molecule of diphosphorus pentoxide. Or you could specify any number of moles. One mole of P2O5 would be 6.022 x 1023 molecules of P2O5. Two moles would be 1.204 x 1024 molecules, and so on.
P2O5 2 atoms of phosphorous 5 atoms of oxygen ------------------------------+ 7 atoms altogether
5, the subscript immediately after the atomic symbol O for oxygen.
To find the number of atoms in 740 g of P2O5, we need to first convert the mass to moles using the molar mass of P2O5, which is 141.94 g/mol. Then, we can use Avogadro's number (6.022 x 10^23) to find the number of atoms. So, 740 g of P2O5 is equal to approximately 5.21 moles, which is equivalent to 3.14 x 10^24 atoms.
In one molecule of diphosphorus pentoxide (P2O5), there are 5 oxygen atoms. So, in 5.00 mol of P2O5, there would be 5.00 mol * 5 = 25.00 moles of oxygen atoms.
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).
18 atoms in total.